Answer:
smart dot company would be c=.50t+12
communication plus would be c=2.50t
Step-by-step explanation:
smart dot starts with $12 a month and adds $0.50 for each hour of internet use. communication plus has no starting fee so it just adds $2.50 for each hour of internet use.
So then for the table you would put the number given for time in for the letter t and find what c would be. This would then find your cost for that amount of hours. To get you started smart dot company starts off with 0 hours so put that in for t being c=0.50(0)+12 and c=12. Communication plus also starts with 0 so it would be c=2.50(0) and c=0
Then you graph once you have both values you can graph having x=time and y=cost
Let me know if this helps!
By using scientific notation we calculated (2.3
10⁵)(1.5 10⁴) we got 345 10⁷.
Given that,
(2.310⁵)(1.5 10⁴)
By using scientific notation
The scientific notation allows us to express extremely large or extremely small numbers by multiplying them by single-digit integers and by 10 raised to the power of the corresponding exponent. The exponent is either positive or negative depending on how big or little the number is.
Now, we calculate
(2.310⁵)=2.5100000=230000
(1.5 10⁴)=1.510000=15000
Now,
=23000015000
=3450000000
=345 10⁷
Therefore, By using scientific notation we calculated (2.310⁵)(1.5 10⁴) we got 345 10⁷.
To learn more about scientific notation visit: brainly.com/question/18073768
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Answer:
32 is 40% of 80
Step-by-step explanation:
i just asked my alexa lol ._.
Answer:
5
Step-by-step explanation:
Answer:
13.60 See the note below.
Step-by-step explanation:
Remark
This is just the reverse of the question you just did. This time you are trying to solve for c
Givens
Solution
c^2 = a^2 + b^2 Substitute the givens.
c^2 = 8^2 + 11^2 Expand
c^2 = 64 + 121 Combine the right side by adding
c^2 = 185 Take the square root of both sides.
sqrt(c^2) = sqrt(185) Complete the operation
c = 13.601 Round to the nearest 1/100 th
c = 13.60 Note: the zero must be there or the answer does not show the nearest 1/100 th
