1. Consider y=f(x)
2. let a and b be 2 positive numbers
3. then the graph of y=f(x)-a is the graph of y=f(x) shifted a units down
4. the graph of y=f(x+b) is y=f(x) shifted b units left
y=f(x-b) is y=f(x) shifted b units right
5. y=f(x+b)-a is the graph of y=f(x) shifted a units down and b units left
6. So
shifted 4 units down and 5 units left is the graph of
7. To check: consider
at x=3. We have the point (3, 27)
Shift this point 4 units down and 5 units left: (3-5, 27-4)=(-2, 23)
Consider
for x=-2
Check the picture below.
so. the x-coordinate of K will then be at
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The area of a sector of a circles is calculated by the equation A = πr^2 (theta/360). From the data of the sector, we determine the radius of the circle. THen, we can calculate for the area of the circle.
16.4π = πr^2 (72/360)
r = 9.06
Area of circle = πr^2
Area of circle = π(9.06)^2
Area of circle = 82π
159mi/3hr = 53 mi/hr. Hope this helps
Answer:
Y=21
Step-by-step explanation:
add 13 on both sides you get Y=21