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viva [34]
4 years ago
7

6200 divided by 163 i need the answer or ill fail

Mathematics
1 answer:
damaskus [11]4 years ago
3 0

Answer:

38.04

Step-by-step explanation:

6200/163= 38.036809816

Since after the 3 is a 6 which is over 5 you can round the 3 up to a 4 and cut everything else off.

Hope this helps. Plz give brainliest.

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What are the zeros of f(x) = x^2 - x - 12?
REY [17]

Answer:

B. x = -3 and x = 4

General Formulas and Concepts:

<u>Algebra I</u>

  • Terms/Coefficients
  • Factoring
  • Solving quadratics

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

f(x) = x² - x - 12

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Factor:                                                                                                               (x - 4)(x + 3) = 0
  2. Solve:                                                                                                                 x = 4, -3
6 0
3 years ago
What is the probability of spinning the spinner and the arrow landing on the number ‘1’ and then spinning it a second time and i
Radda [10]

Answer:

There isn't a picture, but i'm guessing they are on opposite ends. If so, it would be 50-50.

Step-by-step explanation:

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4 0
4 years ago
A person is standing close to the edge on a 56 foot building and throws the ball vertically upward. The quadratic function h(t)=
Romashka [77]

Answer:

Part 1)

225 feet.

Part 2)

7 seconds.

Step-by-step explanation:

The height h(t) of the ball above the ground after <em>t</em> seconds is modeled by the function:

h(t)=-16t^2+104t+56

Part 1)

We want to determine the maximum height of the ball.

Notice that the function is a quadratic with a negative leading coefficient, so its maximum will be at its vertex point.

The vertex of a parabola is given by:

\displaystyle \text{Vertex} = \left(-\frac{b}{2a}, f\left(-\frac{b}{2a}\right)\right)

In this case, <em>a</em> = -16, <em>b</em> = 104, and <em>c</em> = 56.

Find the <em>x-</em> (or rather <em>t-</em>)<em> </em>coordinate of the vertex. So:

\displaystyle t=-\frac{(104)}{2(-16)}=\frac{104}{32}=\frac{13}{4}=3.25\text{ seconds}

In other words, the ball reaches its maximum height after 3.25 seconds.

To find the maximum height, substitute this value back into the function. Hence:

\displaystyle h(3.25)=-16(3.25)^2+104(3.25)+56=225\text{ feet}

The maximum height of the ball is 225 feet in the air.

Part 2)

We want to find the amount of time it took for the ball to hit the ground.

When the ball hit the ground, its height above the ground is zero. Therefore, we can set h(t) to 0 and solve for <em>t: </em>

0=-16t^2+104t+56

We can simplify a bit. Divide both sides by -8:

0=2t^2-13t-7

We can factor. Find two numbers that multiply to 2(-7) = -14 and add to -13.

-14 and 1 works! Therefore, split the second term into -14 and 1:

\displaystyle 0=2t^2-14t+t-7

Factor out a 2<em>t</em> from the first two terms and group the last two terms:

0=2t(t-7)+(t-7)

Factor by grouping:

0=(2t+1)(t-7)

Zero Product Property:

2t+1=0\text{ or } t-7=0

Solve for each case:

\displaystyle t=-0.5\text{ or } t=7

Since time cannot be negative, we can ignore the first case.

Therefore, it takes seven seconds for the ball to hit the ground.

6 0
3 years ago
The coordinates of the vertices of △PQR are P(1, 4) , Q(2, 2) , and R(−2, 1) . The coordinates of the vertices of △P′Q′R′ are P′
sveticcg [70]

ANSWER


The correct  answer is B


<u>EXPLANATION</u>

If we analyse the coordinates carefully, you realize there is a mapping of

(x,y)\rightarrow(-x,y)

This is a reflection in the y-axis.


Since the transformation is a reflection, the shape is preserved. Therefore, the image triangle P'Q'R' of triangle

PQR are congruent.



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