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zheka24 [161]
3 years ago
13

The campus bookstore has estimated that it's profit (in dollars) from selling x hundred basketball conference championship t-shi

rts is given by the equation shown below.
p=-40x^2+581x-520

The demand is currently 500 t-shirts, but euphoria over the championship is subsiding so the demand is dropping by 100 t-shirts per day. how is the profit changing with respect to time?
$____per day
Mathematics
1 answer:
alina1380 [7]3 years ago
3 0

Answer:

-$80

Step-by-step explanation:

Assuming that the variation in the number of shirts per day is -1 hundred shirs, the variation in profit with respect to time is given by the derivate of the profit equation:

p=-40x^2+581x-520\\\frac{dp}{dx}=-80x+581

Let x be the number of shirts sold in a day, then x-1 is the number of shirts sold in the following day, the change in profit is:

p'(x) - p'(x-1)=-80x+581 - (-80(x-1)+581)\\p'(x) - p'(x-1)=-80(x-x+1) = -80

The profit is changing by -$80 per day.

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<u>Step-by-step explanation:</u>

Here we have , Twenty-eight athletes participate in a 100-meter race. The time of each athlete is measured during the qualification round. The average time is 11 seconds. The 8 athletes with the fastest time qualified for the final. The average time of these 8 athletes is 10.5 seconds. Let's have equations for this:

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