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atroni [7]
3 years ago
9

When a puppy was brought home it weighed 22 ounces.After two years, the puppy had grown into a dog weighing 310 ounces.How many

ounces did the puppy gain
Mathematics
1 answer:
Kruka [31]3 years ago
7 0

Answer:

288 oz

Step-by-step explanation:

310(final weight)-22(original weight)=288(weight gained)

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A come and a pyramid has equal heights and volumes.if the base area of the pyramid is 154cm2.find the radius of the cone.
Dmitry_Shevchenko [17]

Answer:

Radius = 8.575 cm

Step-by-step explanation:

Formula for volume of a pyramid is;

V_p = ½Ah

Where A is area of base and h is height

Also, formula for volume of cone is given as;

V_c = ⅓πr²h

Now, we are told that V_p = V_c and that h is the same for both shapes.

Thus ;

½Ah = ⅓πr²h

h will cancel out to give;

½A = ⅓πr²

Cross multiply to give;

3A/2π = r²

Base area of pyramid is given as 154 cm². Thus;

(3 × 154)/2π = r²

r = √((3 × 154)/2π

r = 8.575 cm

4 0
3 years ago
Someone help plz plz
Rashid [163]

Answer:

8

Step-by-step explanation:

don't start with 2, start with 0

6 0
3 years ago
Read 2 more answers
A rock is thrown upward with an initial velocity of 16 ft/s from an initial height of 5 ft. How much time does it take for the r
Bogdan [553]
Check the picture below.

so it hits the ground when y = 0, thus

\bf ~~~~~~\textit{initial velocity}\\\\
\begin{array}{llll}
~~~~~~\textit{in feet}\\\\
h(t) = -16t^2+v_ot+h_o
\end{array} 
\quad 
\begin{cases}
v_o=\stackrel{16}{\textit{initial velocity of the object}}\\\\
h_o=\stackrel{5}{\textit{initial height of the object}}\\\\
h=\stackrel{}{\textit{height of the object at "t" seconds}}
\end{cases}

\bf h(t)=-16t^2+16t+5\implies \stackrel{h(t)}{0}=-16t^2+16t+5
\\\\\\
16t^2-16t-5=0\implies (4t+1)(4t-5)=0\\\\
-------------------------------\\\\
4t+1=0\implies 4t=-1\implies t=-\cfrac{1}{4}\\\\
-------------------------------\\\\
4t-5=0\implies 4t=5\implies t=\cfrac{5}{4}\implies \boxed{t=1\frac{1}{4}}

since "t" is seconds it took, it can't be a negative amount.

5 0
3 years ago
Which expressions are equivalent to the one below?check all that apply.
sineoko [7]
The answers for the question shown above are the option A, the option B and the option C, which are:
 A.log5(15625)
<span> B.log5(5^6)
 C.6
 The explanation is shown below:
 By applying the logarithms properties, you have:
 A. </span><span>log5(125)+log5(125)=log5(125)(125)=log5(15625)
 B. </span>log5(125)+log5(125)=log5(15625)=log5(5^6)
 C. og5(125)+log5(125)=log5(15625)=log5(5^6)=6log5(5)=6
3 0
3 years ago
Read 2 more answers
A leather store performs an observational survey of women walking through a mall. There were 30 women that walked by in an hour.
Blababa [14]

Answer:

Step-by-step explanation:

let's call B the event that a woman was wearing a belt and C the event that a woman was carrying a purse.

The probability P(B/C) that a woman was wearing a belt, given that the woman was also carrying a purse can be calculated as:

P(B/C) = P(B∩C)/P(C)

Where P(C) is the probability that a woman was carrying purse and P(B∩C) is the probability that the woman was both carrying purse and wearing belt.

So, P(C) is calculated as:

P(C) = 18 / 30 = 0.6

Because there were 30 women that walked by in an hour and of those women, 18 were carrying purses.

At the same way, P(B∩C) is equal to:

P(B∩C) = 6 / 30 = 0.2

Finally, P(B/C) is equal to:

P(B/C) = 0.2/0.6 = 0.3333

6 0
3 years ago
Read 2 more answers
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