Ask question

Ask question

All categories

anzhelika [568]

2 years ago

10

Kyleigh put a large rectangular sticker on her notebook. The height of the sticker measures 14 centimeters. The base is half as

long as the height.
What area of the notebook does the sticker cover?

1 answer:

Mamont248 [21]2 years ago

8 0

Answer:

The answer is 98 square cm

Step-by-step explanation:

14/2=7

14*7=98

You might be interested in

Which of the following expressions is the conjugate of a complex number with 2 as the real part and 3i as the imaginary part?

lbvjy [14]

The complex number is represented as 2 + 3i. The conjugate of the complex number is the number with equal real part and imaginary part equal in magnitude but opposite in sign. Therefore, the correct answer is option B. The conjugate of the complex number is 2 − 3i.

4 0

3 years ago

Read 2 more answers

FIRST RIGHT ANSWER GETS BRAINLIEST

Shtirlitz [24]

Answer:

what's the question

Step-by-step explanation:

........

3 0

3 years ago

How do I simplify 10q-2q+3-9?

Viktor [21]

Answer:

The answer should be 8q-6 i think i tried

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Solve the given initial-value problem. the de is of the form dy dx = f(ax + by + c), which is given in (5) of section 2.5. dy dx

shutvik [7]

$\dfrac{\mathrm dy}{\mathrm dx}=\cos(x+y)$

Let $v=x+y$ , so that $\dfrac{\mathrm dv}{\mathrm dx}-1=\dfrac{\mathrm dy}{\mathrm dx}$ :

$\dfrac{\mathrm dv}{\mathrm dx}=\cos v+1$

Now the ODE is separable, and we have

$\dfrac{\mathrm dv}{1+\cos v}=\mathrm dx$

Integrating both sides gives

$\displaystyle\int\frac{\mathrm dv}{1+\cos v}=\int\mathrm dx$

For the integral on the left, rewrite the integrand as

$\dfrac1{1+\cos v}\cdot\dfrac{1-\cos v}{1-\cos v}=\dfrac{1-\cos v}{1-\cos^2v}=\csc^2v-\csc v\cot v$

Then

$\displaystyle\int\frac{\mathrm dv}{1+\cos v}=-\cot v+\csc v+C$

and so

$\csc v-\cot v=x+C$

$\csc(x+y)-\cot(x+y)=x+C$

Given that $y(0)=\dfrac\pi2$ , we find

$\csc\left(0+\dfrac\pi2\right)-\cot\left(0+\dfrac\pi2\right)=0+C\implies C=1$

so that the particular solution to this IVP is

$\csc(x+y)-\cot(x+y)=x+1$

5 0

3 years ago

Please help me,ASAP

pav-90 [236]

Answer:

b. They can both be 90 degree angles

c. Acute angles are by definition 90 degrees, and acute is less than but not equal to 90 degrees

d. should be always

e. should be never (explanation: they have to be adjacent to be supplementary, and vertical angles are never adjacent)

Step-by-step explanation:

8 0

3 years ago