Answer:
All the potential root of f(x) are
.
Step-by-step explanation:
According to the rational root theorem, all the potential root of f(x) are defined as
![x=\pm\frac{p}{q}](https://tex.z-dn.net/?f=x%3D%5Cpm%5Cfrac%7Bp%7D%7Bq%7D)
Where, p is factor of constant term and q is factor of leading coefficient.
The given function is
![f(x)=9x^8+9x^6-12x+7](https://tex.z-dn.net/?f=f%28x%29%3D9x%5E8%2B9x%5E6-12x%2B7)
Here, constant term is 7 and leading coefficient is 9.
Factors of 7 are ±1, ±7 and the factors of 9 are ±1, ±3, ±9.
Using rational root theorem, all the potential root of f(x) are
![x=\pm 1,\pm7, \pm \frac{1}{3},\pm \frac{7}{3}, \pm \frac{1}{9},\pm \frac{7}{9}](https://tex.z-dn.net/?f=x%3D%5Cpm%201%2C%5Cpm7%2C%20%5Cpm%20%5Cfrac%7B1%7D%7B3%7D%2C%5Cpm%20%5Cfrac%7B7%7D%7B3%7D%2C%20%5Cpm%20%5Cfrac%7B1%7D%7B9%7D%2C%5Cpm%20%5Cfrac%7B7%7D%7B9%7D)
Therefore all the potential root of f(x) are
.