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Vlada [557]
4 years ago
9

The length of a park is 250 meters. What is the length of the park in kilometers

Mathematics
1 answer:
Tatiana [17]4 years ago
4 0
0.25 kilometers
Using the universal measurement
Kilo, hecto, deca, unit, deci, centi, milli
Kilometer, hectometer, decameter, meter, decimeter, centimeter, millimeter

From unit you would move three time to the left from your decimal point on your starting number 250. You would move it three times to the left because meter to kilometer is three decimals to the left

A way I remember my universal measurements is king (k-kilo), Henry (h-hecto), died (d-deca), unexpectedly (u-unit as in liters, meters, grams) drinking (d-deci), chocolate (c-centi) milk (m-milli)
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How do u simply stuff like this​
Stells [14]

To simplify stuff like this,divide the numerator by the denominator.

For example-15/4

15/4=3 with a remainder of 3

therefore, it would be 3 3/4

7 0
3 years ago
Which two numbers on the number line have an absolute value of 4?
iris [78.8K]

Answer:

-4 and 4

Step-by-step explanation:

absolute value is decide how far a number is from 0 on the number line.

4 0
3 years ago
F(n)=4n-3 find the 15th term of the sequence defined by the explicit rule
pickupchik [31]

Answer:

57

Step-by-step explanation:

f(15)=4(15)-3

f(15)=60-3

f(15)=57

Hope that helps, tell me if you need more help

7 0
3 years ago
Read 2 more answers
Given any two numbers which is greater the LCM of the numbers or the GCF of the number? Why?
Natali [406]
The LCM  is the greater.

The GCF  is a factor which  divides in to each number  so can never be equal to the greater number, whereas the LCM is   the greater of the 2 numbers or  a multiple of them
7 0
3 years ago
The estimated daily living costs for an executive traveling to various major cities follow. The estimates include a single room
Alexandra [31]

Answer:

\bar x = 260.1615

\sigma = 70.69

The confidence interval of standard deviation is: 53.76 to 103.25

Step-by-step explanation:

Given

n =20

See attachment for the formatted data

Solving (a): The mean

This is calculated as:

\bar x = \frac{\sum x}{n}

So, we have:

\bar x = \frac{242.87 +212.00 +260.93 +284.08 +194.19 +139.16 +260.76 +436.72 +355.36 +.....+250.61}{20}

\bar x = \frac{5203.23}{20}

\bar x = 260.1615

\bar x = 260.16

Solving (b): The standard deviation

This is calculated as:

\sigma = \sqrt{\frac{\sum(x - \bar x)^2}{n-1}}

\sigma = \sqrt{\frac{(242.87 - 260.1615)^2 +(212.00- 260.1615)^2+(260.93- 260.1615)^2+(284.08- 260.1615)^2+.....+(250.61- 260.1615)^2}{20 - 1}}\sigma = \sqrt{\frac{94938.80}{19}}

\sigma = \sqrt{4996.78}

\sigma = 70.69 --- approximated

Solving (c): 95% confidence interval of standard deviation

We have:

c =0.95

So:

\alpha = 1 -c

\alpha = 1 -0.95

\alpha = 0.05

Calculate the degree of freedom (df)

df = n -1

df = 20 -1

df = 19

Determine the critical value at row df = 19 and columns \frac{\alpha}{2} and 1 -\frac{\alpha}{2}

So, we have:

X^2_{0.025} = 32.852 ---- at \frac{\alpha}{2}

X^2_{0.975} = 8.907 --- at 1 -\frac{\alpha}{2}

So, the confidence interval of the standard deviation is:

\sigma * \sqrt{\frac{n - 1}{X^2_{\alpha/2} } to \sigma * \sqrt{\frac{n - 1}{X^2_{1 -\alpha/2} }

70.69 * \sqrt{\frac{20 - 1}{32.852} to 70.69 * \sqrt{\frac{20 - 1}{8.907}

70.69 * \sqrt{\frac{19}{32.852} to 70.69 * \sqrt{\frac{19}{8.907}

53.76 to 103.25

8 0
3 years ago
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