we know that
The measurement of the exterior angle is the semi-difference of the arcs which comprises
In this problem
∠FGH is the exterior angle
∠FGH=
∠FGH=
-----> equation A
--------> equation B
Substitute equation B in equation A
![100\°=(arc\ FEH-[360\°-arc\ FEH])](https://tex.z-dn.net/?f=100%5C%C2%B0%3D%28arc%5C%20FEH-%5B360%5C%C2%B0-arc%5C%20FEH%5D%29)
therefore
<u>The answer is</u>
The measure of arc FEH is equal to 
Using the asymptote concept, the function with a vertical asymptote at x = 3 and an horizontal asymptote at 
is given by:
<h3>What are the asymptotes of a function f(x)?</h3>
- The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.
- The horizontal asymptote is the value of f(x) as x goes to infinity, as long as this value is different of infinity.
The vertical asymptote at x = 3 means that x = 3 is a root of the denominator, hence:
The horizontal asymptote at y = -1/2 means that:
Which happens if 
, hence the function is:
More can be learned about asymptotes at brainly.com/question/16948935
#SPJ1
Answer:
it's 12
Step-by-step explanation:
2 and 2/5 divide by 1/5 is 12
<h2>C. ΔQRS ≅ ΔGFE </h2>
ΔQRS ≅ ΔGFE because :
∠Q = ∠G = 55°( corresponding part )
∠R = ∠F = 60° ( corresponding part )
∠S = ∠E = 65° ( corresponding part )
QS = GE = 16 ( corresponding part )
Therefore , the correct answer is :-
<h3>C. ΔQRS ≅ ΔGFE </h3>
1. Answer: 19/30 or 0.63
2. Answer: 11/20 or 0.55
3. Answer: 7/4 or 1 3/4 or 1.75
