a) –a + b is negative
b) a – b is positive
c) b-a is negative
Step-by-step explanation:
1. Suppose a and b are real numbers where a > 0 and b < 0.
a. Is –a + b positive or negative. Explain how you know.
We know a > 0 and b < 0. so, let a =6 and b = -5
Putting values:
–a + b
= -(6)+(-5) = -6-5 = -11
So, –a + b is negative
b. Is a – b positive or negative? Explain how you know.
We know a > 0 and b < 0. so, let a =6 and b = -5
Putting values:
a - b
=6-(-5) = 6+5 = 11
So, a – b is positive
c. Is b – a positive or negative. Explain how you know
We know a > 0 and b < 0. so, let a =6 and b = -5
Putting values:
b-a
=(-5)-(6)
= -5-6
= -11
So, b-a is negative
Keywords: Solving Integers:
Learn more about solving integers at:
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Answer:
One equation would be y= -1.5x +11
Step-by-step explanation:
Here's a table to show the coordinates
x: y:
8 -1
-------------------
-4 17
the x coor. 8 goes down by 12 to get to the next x coor. -4.
8-12= -4
the y coor. -1 goes up by 18 to get to the next y coor. 17.
-1+18= 17
therefore 18/-12 is -1.5 which can be your k in y=kx+b.
Check your answer.
-1.5*8= -12 but when you add 11, you get the y coor. -1
Do the same with the other x coor.
-4*-1.5= 6 + 11 =17
11 can be your b in the slope-intercept form equation.
One equation may be y = -1.5x +11
Answer:
468
Step-by-step explanation:
The answer for this question is 0.55%
Answer:
a) 0.2416
b) 0.4172
c) 0.0253
Step-by-step explanation:
Since the result of the test should be independent of the time , then the that the test number of times that test proves correct is independent of the days the river is correct .
denoting event a A=the test proves correct and B=the river is polluted
a) the test indicates pollution when
- the river is polluted and the test is correct
- the river is not polluted and the test fails
then
P(test indicates pollution)= P(A)*P(B)+ (1-P(A))*(1-P(B)) = 0.12*0.84+0.88*0.16 = 0.2416
b) according to Bayes
P(A∩B)= P(A/B)*P(B) → P(A/B)=P(A∩B)/P(B)
then
P(pollution exists/test indicates pollution)=P(A∩B)/P(B) = 0.84*0.12 / 0.2416 = 0.4172
c) since
P(test indicates no pollution)= P(A)*(1-P(B))+ (1-P(A))*P(B) = 0.84*0.88+ 0.16*0.12 = 0.7584
the rate of false positives is
P(river is polluted/test indicates no pollution) = 0.12*0.16 / 0.7584 = 0.0253
