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maksim [4K]
3 years ago
9

4a + 7b + 3a – 2b + 2a

Mathematics
1 answer:
zzz [600]3 years ago
4 0
9a plus 9b equals 81
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Using complete sentences, describe how you would check the quotient of two rational expressions. Create and demonstrate your own
Kamila [148]
<span>To check the quotient of a division problem, I would multiply the quotient by the divisor and add the remainder. If the quotient is correct, the result will be the dividend.
example is below
</span><span><span><span><span>x2</span>−x−6/</span><span>x−3</span></span>=<span><span>(x−3)(x+2)/</span><span>x−3</span></span>=x+2</span>
6 0
3 years ago
I need you to answer with a, b, c, d
solong [7]

To find the zeros of a quadratic fiunction given the equation you can use the next quadratic formula after equal the function to 0:

\begin{gathered} ax^2+bx+c=0 \\  \\ x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \end{gathered}

For the given function:

f(x)=2x^2-10x-3x=\frac{-(-10)\pm\sqrt[]{(-10)^2-4(2)(-3)}}{2(2)}x=\frac{10\pm\sqrt[]{100+24}}{4}\begin{gathered} x=\frac{10\pm\sqrt[]{124}}{4} \\  \\ x=\frac{10\pm\sqrt[]{2\cdot2\cdot31}}{4} \\  \\ x=\frac{10\pm\sqrt[]{2^2\cdot31}}{4} \\  \\ x=\frac{10\pm2\sqrt[]{31}}{4} \\  \end{gathered}\begin{gathered} x_1=\frac{10}{4}+\frac{2\sqrt[]{31}}{4} \\  \\ x_1=\frac{5}{2}+\frac{\sqrt[]{31}}{2} \end{gathered}\begin{gathered} x_2=\frac{10}{4}-\frac{2\sqrt[]{31}}{4} \\  \\ x_2=\frac{5}{2}-\frac{\sqrt[]{31}}{2} \end{gathered}

Then, the zeros of the given quadratic function are:

\begin{gathered} x=\frac{5}{2}+\frac{\sqrt[]{31}}{2} \\  \\ x_{}=\frac{5}{2}-\frac{\sqrt[]{31}}{2} \end{gathered}

Answer: Third option

8 0
1 year ago
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3 years ago
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If x divided 9=9 how do u know what x is
Volgvan
X is 1 because if you times it by x it equals it number
7 0
3 years ago
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What is the slope of the line that is perpendicular to the given line x-2y=10?
Anuta_ua [19.1K]

Answer: slope = 1/2

Step-by-step explanation:

X-2y=10

-2y=-x-10 subtract x from both sides

2y=x+10 divide by -1

y=<u>1</u> x + 5 Divide by 2

  2

slope = 1/2

6 0
3 years ago
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