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Oduvanchick [21]
3 years ago
5

If you know that 4 of an item costs a certain amount, and you want to find out how much one costs, which operation will you use?

Mathematics
2 answers:
Natalija [7]3 years ago
6 0

Answer:

The answer would be division (B)

Step-by-step explanation:

4x equals the total amount

x equals the cost of one item

Therefore you'd divide total cost by 4 and that would find the cost of one item

ziro4ka [17]3 years ago
5 0

Answer:

We will use division operation

Step-by-step explanation:

Let x be the cost of 4 items

So, cost of 1 item = \frac{x}{4}

So, we have used division operation

So, to find out how much one costs, we will use division operation

So, Option B is true

Hence we will use division operation

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Find the equation of the line which is perpendicular to the line y=− 1 3 x+6 through the point (2,4)
nikklg [1K]

The equation of the perpendicular line is   13y=27-x

Step-by-step explanation:

Writing the given equation to slope-intercept form.

y=− 1 3 x+6

The slope of this line is 13

The perpendicular slope is -1/13

Using  the new slope and the given point into the slope-intercept form to find the y-intercept.  

4=-1/13(2)+c

2=-1/13+c

c=27/13

 y=-1/13x+27/13

So the equation of the perpendicular line is 13y=27-x

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A kite with a string 50 meters long makes an angle of elevation of 58o with the ground, assuming the string is straight, how hig
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String is the hypotenuse
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height = 50 * .84805
height = <span> <span> <span> 42.4025 </span> </span> </span>


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Write a inequality Martin is building a sandcastle at the
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X greater than or equal to 5
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The answer is

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An equilateral triangle is inscribed in a circle of radius 2r. Express the area A within the circle but outside the triangle as
defon

Answer:

A=8\pi r^2-\dfrac{49\sqrt{3}x^2}{4}\ un^2.

Step-by-step explanation:

An equilateral triangle with the side 7x units is inscribed in a circle of radius 2r units.

1. The area of the circle is

A_{circle}=2\pi (2r)^2=2\pi \cdot 4r^2=8\pi r^2\ un^2.

2. The area of the equilateral triangle is

A_{\triangle }=\dfrac{(7x)^2\sqrt{3}}{4}=\dfrac{49\sqrt{3}x^2}{4}\ un^2.

3. The area A within the circle but outside the triangle is

A=A_{circle}-A_{\triangle}=8\pi r^2-\dfrac{49\sqrt{3}x^2}{4}\ un^2.

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