I think it is A. not sure though
Answer:
15.59 feet
Step-by-step explanation:
We need to find BC and CD
First find BC
We can use the Pythagorean theorem
AB^2 + BC^2 = AC^2
11^2 + BC^2 = 13^2
121 + BC^2 =169
Subtract 121 from each side
121-121+BC^2 = 169-121
BC^2 = 48
Take the square of each side
sqrt(BC^2 ) = sqrt( 48)
BC = 6.92820323
then we need to find CD
We can use the Pythagorean theorem
CD^2 + DE^2 = CE^2
CD^2 + 5^2 = 10^2
CD^2 + 25 =100
Subtract 25 from each side
CD^2 + 25-25 =100-25
CD^2 = 75
Take the square of each side
sqrt(CD^2 ) = sqrt( 75)
BC = 8.660254038
BD = BC +CD
= 6.92820323 + 8.660254038
15.58845727
Answer:
127.28 feet
Step-by-step explanation:
Given
Shape of basketball diamond = Square
Length of a side = 90 feet
If the length of a side is 90 feet then the length of other sides is 90 feet.
By finding how far the catcher, at home plate, throw to get the runner "out", we are basically finding the distance from 2nd base to home
This means we're calculating the diagonal of the field..
(Since the field is a square, it has a right angle at 1st base)
Let the diagonal be representing by x.
From Pythagoras,
x² = 90² + 90²
x² = 8100 + 8100
x² = 16200
x = √16200
x = 127.2792206135785
x = 127.28 feet ------ Approximated
238 can be divided by 3, 79 times with a remainder of 3
Hope this helps
The answer is all real numbers
