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3 years ago

Absolute Value Solve each equation. Write your answer as a solution set. lml=14

1 answer:

8 0

Answer: M= 14 or -14

Reason: When the absolute value symbol is around a number it turns it into it how far from 0 is it. And both 14 and -14 are 14 numbers away from 0

Hope this helps

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You are studying for your final exam of the semester. up to this point, you received 3 exam scores of 67%, 68%, and 78℅. to rece

scoray [572]

(67 + 68 + 78 + x) / 4 = 70
(213 + x) / 4 = 70
213 + x = 70 * 4
213 + x = 280
x = 280 - 213
x = 67

(213 + x) / 4 = 79
213 + x = 79 * 4
213 + x = 316
x = 316 - 213
x = 103

lowest u can make is 67, highest u can make is 100

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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Leya [2.2K]

Answer:

y , add 7, multiply by 3, then subtract 6.or Solve the system of equations and choose the correct answer from the list of options. x − y = 7 y = 3x + 12 2 over 19 comma 2 over 33 negative 2 over 19 comma negative 33 over 2 negative 19 over 2 comma negative 33 over 2 19 over 2 comma 33 over 2

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2 years ago

A gambler has a coin which is either fair (equal probability heads or tails) or is biased with a probability of heads equal to 0

yawa3891 [41]

Answer:

(a) 0.1719

(b) 0.3504

Step-by-step explanation:

For every coin the number of heads follows a Binomial distribution and the probability that x of the 10 times are heads is equal to:

$P(x)=\frac{n!}{x!(n-x)!}*p^x*(1-p)^{10-x}$

Where n is 10 and p is the probability to get head. it means that p is equal to 0.5 for the fair coin and 0.3 for the biased coin

So, for the fair coin, the probability that the number of heads is less than 4 is:

$P(x$

Where, for example, P(0) and P(1) are calculated as:

$P(0)=\frac{10!}{0!(10-0)!}*0.5^0*(1-0.5)^{10-0}=0.0009\\P(1)=\frac{10!}{1!(10-1)!}*0.5^1*(1-0.5)^{10-1}=0.0098$

Then, $P(x$ , so there is a probability of 0.1719 that you conclude that the coin is biased given that the coin is fair.

At the same way, for the biased coin, the probability that the number of heads is at least 4 is:

$P(x\geq4 )=P(4)+P(5)+P(6)+...+P(10)$

Where, for example, P(4) is calculated as:

$P(4)=\frac{10!}{4!(10-4)!}*0.3^4*(1-0.3)^{10-4}=0.2001$

Then, $P(x\geq4 )=0.3504$ , so there is a probability of 0.3504 that you conclude that the coin is fair given that the coin is biased.

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3 years ago

Find a linear inequality with the following solution set. Each grid line represents one unit.

bekas [8.4K]

The equation of the line is y = 3x - 4, so the inequality is y <= 3x - 4.

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3 years ago

*Absolute Value* Solve each equation. Write your answer as a solution set. lml=14

Absolute Value Solve each equation. Write your answer as a solution set. lml=14