The length of ST to the nearest tenth of a foot is 5.2 ft
Step-by-step explanation:
Here we have
∡T = 90°
∡R = 64°
RS = 5.8 ft
To answer the question, we have apply sine rule as follows;
Therefore, for triangle RST, we will have;
Therefore;
from which
Therefore, the length of ST to the nearest tenth of a foot = 5.2 ft.
Answer:
(f∘f)(x) = x⁴ -12x² +30
(g∘g)(x) = x/9
Step-by-step explanation:
a) (f∘f)(x) = f(f(x)) = f(x² -6)
... = (x² -6)² -6
... = x⁴ -12x² +36 -6
... (f∘f)(x) = x⁴ -12x² +30
b) (g∘g)(x) = g(g(x)) = g(x/3)
... = (x/3)/3
... (g∘g)(x) = x/9
Answer:
![\displaystyle Yes \\ Range: Set-Builder\:Notation → [f(x)|-2 ≤ f(x) ≤ 4] \\ Interval\:Notation → [-2, 4] \\ \\ Domain: Set-Builder\:Notation → [x|0 ≤ x ≤ 7] \\ Interval\:Notation → [0, 7]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Yes%20%5C%5C%20Range%3A%20Set-Builder%5C%3ANotation%20%E2%86%92%20%5Bf%28x%29%7C-2%20%E2%89%A4%20f%28x%29%20%E2%89%A4%204%5D%20%5C%5C%20Interval%5C%3ANotation%20%E2%86%92%20%5B-2%2C%204%5D%20%5C%5C%20%5C%5C%20Domain%3A%20Set-Builder%5C%3ANotation%20%E2%86%92%20%5Bx%7C0%20%E2%89%A4%20x%20%E2%89%A4%207%5D%20%5C%5C%20Interval%5C%3ANotation%20%E2%86%92%20%5B0%2C%207%5D)
Step-by-step explanation:
Just by looking at the graph vertically and horisontally, you can tell what the range and domain is, depending on whether the segments are <em>closed</em> or <em>opened</em>.
* This is a function because it passes the <em>vertical</em><em> </em><em>line test</em>.
** This is kind of like a sine wave.
I am joyous to assist you anytime.