Answer:
30 out of 40: 75%
40 out of 50: 80%
40 out of 50 is the better score
Answer:
x^2 – 3xy + 2y^2
Step-by-step explanation:
Factor the following:
x^2 - 3 x y + 2 y^2
Hint: | Factor the quadratic x^2 - 3 x y + 2 y^2.
The factors of 2 that sum to -3 are -1 and -2. So, x^2 - 3 x y + 2 y^2 = (x - 1 y) (x - 2 y):
Answer: (x - y) (x - 2 y)
The answer is 20
Reason: so the W is 4 and the L is 6 so you do 4+4=8 then you do 6+6=12 then you add the two together and get 20
Answer:
Step-by-step explanation:
From the picture attached,
Addition of the blocks in first row is 60
a + a + a + 12 = 60
3a + 12 = 60
3a = 60 - 12
3a = 48
a = 16
For second row,
(b + 5) + (b + 5) + (b + 5) + (b + 5) = 60
4(b + 5) = 60
b + 5 = 15
b = 10
For third row,
(a + b) + c = (b + 5) + (b + 5) + (b + 5)
a + b + c = 3(b + 5)
16 + 10 + c = 3(10 + 5) [Since, a = 16 and b = 10}
26 + c = 45
c = 45 - 26
c = 19
For fourth row,
3c + d = 60
3(19) + d = 60
57 + d = 60
d = 60 - 57
d = 3
Let AB be a chord of the given circle with centre and radius 13 cm.
Then, OA = 13 cm and ab = 10 cm
From O, draw OL⊥ AB
We know that the perpendicular from the centre of a circle to a chord bisects the chord.
∴ AL = ½AB = (½ × 10)cm = 5 cm
From the right △OLA, we have
OA² = OL² + AL²
==> OL² = OA² – AL²
==> [(13)² – (5)²] cm² = 144cm²
==> OL = √144cm = 12 cm
Hence, the distance of the chord from the centre is 12 cm.
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