So 2 gallons every 5 minutes
2/5= .4
so .4 a minute
and you already have 5 gallons in so those need to be added
m=minutes
y=0.4m + 5 will be what you want to find out if you are looking to find out how much will be there in a certain time
for 50 minutes you will have
y=0.4(50) +5
20+5
25 gallons
HOWEVER, the equation has to be changed if you want to tell how long you have to wait for it to fill.
m=2.5(g-5)
m=minutes
g= gallons
you subtract 5 because they are already there
you multiply by 2.5 because it fills at a rate of 1 gallon every 2.5 minutes.
m=2.5(1500-5)
for the sake of it being easier i will do the -5 separately
2.5(1500 = 3750
2.5(-5= -12.5
3750-12.5
3737.5 minutes to fill the pool.
3720/60 = 62
17.5/60 = .292
62.292 hours to fill the pool.
p.s. you have a really slow hose.
Its good you didn't wait for it to fill, you would have died from lack of water before then if you just sat and waited.
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Given:
To find:
The quadrant in which 
lie.
Solution:
Quadrant concept:
In Quadrant I, all trigonometric ratios are positive.
In Quadrant II, only 
and 
are positive.
In Quadrant III, only 
and 
are positive.
In Quadrant IV, only 
and 
are positive.
We have,
Here, is negative and is also negative. It is possible, if 
lies in the Quadrant IV.
Therefore, the correct option is D.
Answer:
14 and 16
Step-by-step explanation:
They are the ONLY consecutive even numbers
And also
x and (x+2)
x(x+2)=224 ( product of a number and the consecutive of that number)
x ²+ 2x-224=0
(x+16)(x-14) =0
x=-16 or 14
In this case 14 and (14+2) 14 and 16
The integers are either 14 and 16 or -14 and -16.
Answer:
range = x ≤ 10
Step-by-step explanation:
Given in the question the function
f(x)=10-x^2
The range of a function is the complete set of all possible resulting values of the dependent variable F(x) after we have substituted the domain which is the values of x.
domain = set of all integers
range = x ≤ 10
f(x)=10-x²
since any negative value of x will be positive with squared so we will start from 0
f(0) = 10-0² = 10
f(1) = 10 - 1² = 9 = f(-1) = 10 -(-1)²
....and so on.
Answer:
Step-by-step explanation:
hypotenuse = √(14.4² + 6²) = √243.36 = 15.6 mi
area of triangle = 0.5×6×14.4 = 43.2 mi²
radius of semicircle = 15.6/2 = 7.8
area of semicircle = πr² = 60.84π mi²
total area = 43.2 + 60.84π ≅ 234.33 mi²
