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slamgirl [31]
3 years ago
6

Someone please help??

Mathematics
1 answer:
irga5000 [103]3 years ago
8 0

Answer:

Im not 100% sure but i can tell you it is (D)

Step-by-step explanation:

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\text{The vertex form of a parabola}\\\\y=a(x-h)^2+k\\\\\text{We have the vertex}\ (-2,\ 5)\to h=-2,\ k=5.\\\\\text{Substitute}\\\\y=a(x-(-2))^2+5=a(x+2)^2+5\\\\\text{We have the point}\ (5,\ -4).\\\text{Substitute the coordinates of the point to the equation:}\\\\-4=a(5+2)^2+5\\\\-4=a(7)^2+5\\\\-4=49a+5\qquad|-5\\\\-9=49a\qquad|:49\\\\a=-\dfrac{9}{49}\\\\Answer:\ \boxed{y=-\dfrac{9}{49}(x+2)^2+5}

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What is the slope of the line that contains the point (13,-2) and (3,-2)
ra1l [238]

The slope of the line that contains the point (13,-2) and (3,-2) is 0

<em><u>Solution:</u></em>

Given that we have to find the slope of the line

The line contains the point (13,-2) and (3,-2)

<em><u>The slope of line is given as:</u></em>

m = \frac{y_2-y_1}{x_2-x_1}

Where, "m" is the slope of line

Here given points are (13,-2) and (3,-2)

(x_1, y_1) = (13, -2)\\\\(x_2, y_2) = (3, -2)

<em><u>Substituting the values in formula, we get,</u></em>

m = \frac{-2-(-2)}{3-13}\\\\m = \frac{-2+2}{3-13}\\\\m = 0

Thus the slope of line is 0

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3 years ago
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