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gregori [183]
3 years ago
13

What are the relative frequencies, to the nearest hundredth, of the rows of the two-way table?

Mathematics
1 answer:
sveta [45]3 years ago
6 0

Answer:       A                 B

Group 1     0.25          0.75

Group 2    0.44          0.56

Step-by-step explanation:

Since we have given that

Number of people of A in group 1 = 15

Number of people of B in group 1 = 45

Total number of people in group 1 is given by

15+45=60

Relative frequency of people of A in Group 1 is given by

\frac{15}{60}=0.25

Relative frequency of people of B in Group 1 is given by

\frac{45}{60}=0.75

Similarly, Number of people of A in group 2 = 20

Number of people of B in group 2 = 25

Total number of people in group 2 is given by

20+25=45

Relative frequency of people of A in Group 2 is given by

\frac{20}{45}=0.44

Relative frequency of people of B in Group 2 is given by

\frac{25}{45}=0.56

Hence,        A                 B

Group 1     0.25          0.75

Group 2    0.44          0.56

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3 years ago
Read 2 more answers
45^2 ÷ 78 = ????????
elena55 [62]
\frac{(45)^2}{78}

To solve the problem find the value of (45)^2 at first

(45)^2=2025\frac{2025}{78}=25\text{ R75}

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You can simplify the fraction to be 25/26

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