the area of a circle is A = πr², where r = radius of the circle.
how to find points in the circle? depends on what the scenario is, if you know circle's center and its radius, simply use the distance formula to get any of the points, if you have only the equation of it in standard form, you can use the x,y coordinates with substitution, if you have an sketch, you can get them off the grid, so depends on what you have as components.
8
3/4
x/32
Solve for x, = 24
Subtract 24 from 32
Also another way
4 x n = 32
n = 8
3x8 = 24
Subtract and same result
20.5 is the IQR of the given set of numbers.
In this question, we are given a matrix, and we have to perform the given operation.
The matrix is:
![\left[\begin{array}{ccc}6&-1&|5\\1&-5&|0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D6%26-1%26%7C5%5C%5C1%26-5%26%7C0%5Cend%7Barray%7D%5Cright%5D)
The following operation is given:

In which
is the element at the first line and
is the element at the second line.
Updating the first line:



Thus, the filled matrix will be given by:
![\left[\begin{array}{ccc}0&29&|5\\1&-5&|0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%2629%26%7C5%5C%5C1%26-5%26%7C0%5Cend%7Barray%7D%5Cright%5D)
For another example where row operations are applied on a matrix, you can check brainly.com/question/18546657
Answer:
36
Step-by-step explanation:
28+8=36
8+8=16
BOOM GOT A BRAIN lol