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3 years ago

Translate this sentence into and equation 72 is the product of Rita’s height and 4

1 answer:

7 0

You can use any variable for Rita’s height.

Example:

4 x h= 72

The h is for Rita’s height but you can use any variable :)

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Factor out the greatest common factor. 6x^5-15x^2+12x=?

jok3333 [9.3K]

Answer:

Factor GCF: 3x(2x⁴ - 5x + 4)

Step-by-step explanation:

Simply take out the greatest variable first and then take out the GCF of the numbers to find out factored GCF.

5 0

3 years ago

Brainliest goes to whoever answers correctly try to show work ONLY if you can also if you want more points answer my other quest

dolphi86 [110]

Answer:

Hi, there the answer is C. y=33/2x+425

I tried uploading a picture on how I got, but it keep saying I'm using offensive word, which I didn't but trust me the answer is right

Step-by-step explanation:

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3 years ago

Explain how to estimate the quotient using compatible<br>numbers.plz help fast

Nadya [2.5K]

<h2><u>PLEASE MARK BRAINLIEST!</u></h2>

Answer:

To estimate the quotient, make the fractions "like" fractions. To do this, you need to make the fractions have the same denominator, and turn them into improper fractions.

Step-by-step explanation:

$27\frac{2}{3} = 27 \frac{20}{30}$

$3\frac{9}{10} = 3\frac{27}{30}$

Now the denominators are the same --> they are "like" fractions.

$27\frac{20}{30} + 3\frac{27}{30} = ?$

$27\frac{20}{30} + 3\frac{27}{30} = (27 + 3) + (\frac{20}{30} + \frac{27}{30})$

$27\frac{20}{30} + 3\frac{27}{30} = (30) + (\frac{47}{30})$

$27\frac{20}{30} + 3\frac{27}{30} = (30) + (1 \frac{17}{30})$

$27\frac{20}{30} + 3\frac{27}{30} = 31 \frac{17}{30}$

Your answer is $31\frac{17}{30}$ .

I hope this helps!

3 0

4 years ago

PLEASE HELP I NEED SOMEBODY TO PARAPHRASE THIS FOR ME! I'LL MARK BRAINLIEST!! 50 POINTS!!!

Mrrafil [7]

3x + 4 = 2x + 2
3x - 2x = 2 - 4
x = -2
one solution

3 0

3 years ago

Read 2 more answers

Please help me find x. I really don't get it.

inysia [295]

Answer:

x = 11

Step-by-step explanation:

The relationship between the sine and cosine functions can be written as ...

sin(x) = cos(90 -x)

sin(A) = cos(90 -A) = cos(B) . . . . substituting the given values

Equating arguments of the cosine function, we have ...

90 -(3x+4) = 8x -35

86 -3x = 8x -35

86 +35 = 8x +3x . . . . . add 3x+35 to both sides

121 = 11x . . . . . . . . . . . . collect terms

121/11 = x = 11 . . . . . . . . divide by 11

_____

<em>Comment on the solution</em>

There are other applicable relationships between sine and cosine as well. The result is that there are many solutions to this equation. One set is ...

11 +(32 8/11)k . . . for any integer k

Another set is ...

61.8 +72k . . . . . for any integer k

3 0

3 years ago