Answer:
-6m^2 *n^2
Step-by-step explanation:
formula: (m^x)/(m^y)= m^(x-y)
apply formula for (4m^2)/(2m^-3)
=(4m^(2--3)/(2)
=4m^5/2
divide 4/2
=2m^5
next part 3n^5/(-mn)^3
3n^5/(-mn)^3
expand
=3n^5/ (-m^3*n^3)
=3n^(5-3)/ -m^3
=3n^2/ -m^3
both parts:
(2m^5* 3n^2)/ -m^3
= -(2m^5* 3n^2)/ m^3
= -(2m^(5-3)* 3n^2)/ 1
= -(2m^2* 3n^2)
= -(6m^2*n^2)
= -6m^2 *n^2
Answer:
possible maximum and minimum values : f (1,1), f (-1,-1)
Step-by-step explanation:
Given function :
f(x,y) = x^2 + y^2
constraint = xy = 1
attached below is the detailed solution of the method of using Lagrange method of Multipliers to find the maximum and minimum values of the function
6m times 8m=48m times 6m=288m times 10m equals 2,880
Answer:
16.33628179866692
Step-by-step explanation:
I dont know how far you wanted me to round so you will have to do that part
$29.99=$30
$30-$15=$15
Ace's profit is $15
