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3 years ago

I need help with this

Mathematics

2 answers:

zhenek [66]3 years ago

7 0

Answer:

6 1/5 = 31/5 and 2 3/4 = 11/4 as improper fractions, hope this helps!

Step-by-step explanation:

lisov135 [29]3 years ago

4 0

Answer:

6 1/5 = 31/5

2 3/4 = 11/4

Step-by-step explanation:

6 1/5 = 31/5

2 3/4 = 11/4

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What is the measure of CED?

LiRa [457]

Answer:

try 106, if its not try 108

Step-by-step explanation:

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3 years ago

Solve for x under the assumption that x<0. <br> x-5/x<4

AleksandrR [38]

If you would like to solve the inequality x - 5/x < 4, you can do this using the following steps:

<span>x - 5/x < 4
</span>x^2 - 5 < 4x
x^2 - 4x - 5 < 0
(x - 5) * (x + 1) < 0
x < 0
1. x = 5
2. x = -1

The correct result would be x = -1.

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3 years ago

What is the solution to 1< 25-4x<19?

koban [17]

Hope this helps

Hope you have a good day

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3 years ago

Oliver and layla each built a rectangular prism with centimeter cubes. Both prisms have a volume of 24 cubic centimeters, but th

Nadusha1986 [10]

The volume of a rectangular prism is width×length×width. With the given volume of 24 you could find 2 ways with different sets of numbers that multiply into 24.

Oliver's= 6, 2, 2
Layla, 3, 2, 4

4 0

3 years ago

Someone help me with my math homework pleaseee. Find the volumes of the pyramids and the height is 7cm for the first one.

gregori [183]

$\bf \textit{volume of a pyramid}\\\\
V=\cfrac{1}{3}Bh\qquad 
\begin{cases}
B=\textit{area of the base}\\
h=height
\end{cases}$

now, the first one, on the far-left.... can't see the height.. but I gather you do, now as far as its Base area, well, the bottom is just a 12x12 square, so the area of its base is just 12*12

now, the middle pyramid, has a height of 6, the base is also a square, 8x8, so the Base area is just 8*8

now the last one on the far-right

has a height of 8, the Base is a Hexagon, with sides of 6

$\bf \textit{area of a regular polygon}\\\\
A=\cfrac{1}{4}ns^2cot\left( \frac{180}{n} \right)\qquad 
\begin{cases}
n=\textit{number of sides}\\
s=\textit{length of one side}\\
\frac{180}{n}=\textit{angle in degrees}\\
----------\\
n=6\\
s=6
\end{cases}\\\\\\ A=\cfrac{1}{4}\cdot 6\cdot 6^2\cdot cot\left( \frac{180}{6} \right)$

5 0

3 years ago

I need help with this​

I need help with this