Answer:
Option A (-1, -6)
Option C (10, 49)
Step-by-step explanation:
Two equations are given as y = (x - 2)² - 15 ----------(1)
and -5x + y = -1
y = -1 + 5x ------(2)
We put the value of y from equation 1 in equation 2.
(x -2)² - 15 = 5x - 1
x² + 4 - 4x - 15 = 5x - 1
x²- 4x - 11 = 5x - 1
x² - 4x - 11 - 5x + 1 = 0
x² - 9x - 10 = 0
x² - 10x + x - 10 = 0
x(x - 10) + 1(x - 10) = 0
(x + 1)(x - 10) = 0
x = -1 , 10
Now we put the value of x in equation 2
y = 5(-1) - 1
y = -5 -1 = -6
For x = 10
y = 5×10 - 1 = 50 - 1 = 49
So solutions are (-1, -6) and (10, 49)
First solution is Option A. (-1, -6) and second solution is Option C.(10, 49)