Answer:
4:24 p.m.
Step-by-step explanation:
Figure out how often the buses leave at the same time. This is the same as the least common multiple (LCM) of how often they leave the stadium.
The LCM is found by multiplying the maximum number of each prime factor found in any of the numbers.
The prime factors of a number are found by dividing it by whole numbers until the factors are all prime. Prime numbers only have the factors 1 and itself.
6 = 2 X 3
8 = 2 X 2 X 2
The greatest times 2 repeats is three times.
The greatest times 3 repeats is one time.
2 X 2 X 2 X 3 = 24
The LCM is 24, and the buses have the same leaving times every 24 minutes.
Find 24 minutes after 4:00 p.m. Change the minutes only, which are the numbers right of the colon : .
The buses will next leave together at 4:24 p.m.
First one A second one C third one d 4th one E
Answer:
Twenty-eight billion five hundred forty-two million rupees
28,542,000,000 rupess
or, 28.542 × 10⁹ rupees
Answer: 14 red, 7 green, 44 blue
Step-by-step explanation:
First, use the letter <em>r</em> as a variable to represent the number of red Legos. The number of green Legos (<em>g</em>) is 7 less than the number of red Legos, or <em>g = r-7.</em> The number of blue Legos (b) is 2 more than 3 times the number of red Legos, or <em>b = 3r+2</em>. The total number of Legos is the number of red + green + blue Legos, which can be represented as <em>65 = r+g+b</em>.
Substitute the equations for g and b in. This should give you a final equation of <em>65 = r+(r-7)+(3r+2)</em>. To solve for the number of <u>red</u> Legos, first add up all of the terms to get <em>65 = 5r-5</em>. Now add 5 to each side (70<em> = 5r</em>). Finally, divide each side by 5 (r = 14).
To find the number of <u>green</u> Legos, substitute the number of red Legos (14) into the equation for the green Legos (<em>g = r-7</em>). This should get you the equation <em>g = 14-7</em> which simplifies to g = 7.
To find the number of <u>blue</u> Legos, substitute the number of red Legos (14) into the equation for the blue Legos (<em>b = 3r+2</em>). This gives you the equation <em>b = (3*14)+2.</em> First, multiply 3 and 14 to get <em>b = 42+2</em>. Finally, add them together to get b = 44.
