She has already spent 612, and by adding C 612 has gone ABOVE 2000
So 612 + C MUST be Greater Than 2000
The answer is D
Answer:
A = 1/2 B H area = 1/2 base X height
B = 2 A / H = 2 * 99 / 12 = 16.5 cm
dA / d t = 1/2 * (B dH / dt + H dB / dt)
dB / dt = (2 dA / dt - B dH / dt) / H
dB / dt = (2 * 1.5 cm^2 / min - 16.5 cm * 2 cm / min) / 12 cm
dB / dt = (3 - 33) / 12 cm/min = -2.5 cm/min
Answer:
D
Step-by-step explanation:
Using the Cosine rule to find AC
AC² = BC² + AB² - (2 × BC × AB × cosB )
= 18² + 12² - ( 2 × 18 × 12 × cos75° )
= 324 + 144 - 432cos75°
= 468 - 111.8
= 356.2 ( take the square root of both sides )
AC = 
≈ 18.9
-----------------------------------------
Using the Sine rule to find ∠ A
= 
( cross- multiply )
18.9 sinA = 18 sin75° ( divide both sides by 18.9 )
sinA = 
, then
∠ A = 
( ) ≈ 66.9°
Answer:
A. = 20 in²
B. = 45 ft²
C. = 29.5 ft²
D. = 36 ft²
E. = 28 ft²
Step-by-step explanation:
A. Formula = A = (h_b b)/2 = base 10 ft height_b= 4ft = 20 ft²
B. We have a rectagnle and a triangle: Formula: A = lw
= A = 30 ft² and now the triangle with the same formula as above: A = 15 ft²
30 ft²+15 ft² = 45 ft²
C. we have 2 rectagnle and a triangle: First the small recangle: A= lw = A = 1ft x 2ft = 2ft²
Second rectangle: 5 ft x 4 ft = 20 ft²
Right angeled triangle Formula: (ab)/2 = 3 ft x 5 ft = 7.5 ft²
Add it all together: 2ft²+20ft²+7.5ft² = 29.5 ft²
D. is a rectangle and a triangle: 8 ft x 3 ft = 24ft²
the triangle 8 ft x 2ft = 12 ft²; add 24 ft²+12 ft² = 36ft²
E. is a right-angled triangle (see fromula above) = (14 ft x 4 ft)/2 = 28ft²
Answer:
mean: 38
range: 27
median: 40
Step-by-step explanation:
mean: 40+13+49+52+35 / 5
range: 40 - 13
median : 40
