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3 years ago

Of the 20 flash bulbs in a box, 2 are defective. an inspector will select 2 light bulbs simultaneously and at random from the bo

x. what is the probability that neither of the light bulbs selected will be defective

Mathematics

1 answer:

Shkiper50 [21]3 years ago

4 0

$|\Omega|=C(20,2)=\dfrac{20!}{2!18!}=\dfrac{19\cdot20}{2}=190\\
|A|=C(18,2)=\dfrac{18!}{2!16!}=\dfrac{17\cdot18}{2}=153\\\\
P(A)=\dfrac{153}{190}\approx81\%$

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$\text{Hey there!}$

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$\bf{First, you\ need\ to\ do \ is\ PEMDAS}\\\\\\\text{Parentheses, Exponents, Multiplication, Division,Addition\ \& Subtraction}$

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