Answer:
I'm sorry is there a chart/graph, etc. to give us more information?
Without the added information there is no way for me to answer.
If you repost this question with a picture I would be more than happy to help.
The first step you should do is subtract 32 from both sides so your answer will turn out like this -
F = (9/5) C + 32
-
F - 32 = (9/5)
Then we will multiply both sides by 5.
5 ( F - 32 ) = 9 C
Divide both sides by 9 to isolate C.
(5/9) ( F - 32 ) = C
So the answer is :
C = (5/9) ( F - 32 )
Hope this helps :)
First term: a1 = 151
common difference: d = -14 (we decrease by 14 each time, eg, 151-14 = 137)
nth term of this arithmetic sequence is...
an = a1+d(n-1)
an = 151+(-14)(n-1)
an = 151-14n+14
an = -14n+165
This will be used in the formula below
Sn = n*(a1+an)/2
<span>Sn = n*(151+(-14n+165))/2
</span><span>S26 = 26*(151+(-14*26+165))/2 ... replace every n with 26
</span>S26 = -624
The final answer here is choice C) -624
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The midpoint, where the rest area is, will just be the average of the coordinates of Springfield and Columbus.
Rest Area=((1+7)/2, (-4+1)/2)
Rest Area=(4, -1.5)
The distance between the two cities can be found using the Pythagorean Theorem, which used in the manner is often referred to as the "distance" formula between two points.
d^2=(x2-x1)^2+(y2-y1)
d^2=(7-1)^2+(1--4)^2
d^2=36+25
d^2=61
d=√61 and we are told that each unit is equal to 5.38mi so the distance from Springfield to Columbus is:
D=5.38√61 mi
D≈42.02mi (to nearest hundredth of a mile)
