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11Alexandr11 [23.1K]
3 years ago
12

Some beetles have longitudinal grooves on their elytra, known as __________.

Biology
1 answer:
RoseWind [281]3 years ago
6 0
Striations!
Striations means a series of ridges, furrows, or linear marks, and is used in several ways. In anatomy, striated muscle.
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Which equation best represents the process of photosynthesis ? A. Water+ carbon dioxide (light) > sugars + oxygen B. Sugars +
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A. Water+ carbon dioxide (light) > sugars + oxygen

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Energy is released from ATP when
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Answer: The correct answer for the blank is-

Energy is released from ATP ( adenosine triphosphate) when high energy phosphoanhydride bond ( present between two phosphate) is broken down or hydrolyzed.

This results in the formation of ADP ( adenosine diphosphate) and Pi ( inorganic phosphate).

Therefore, hydrolysis of ATP releases energy.

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How does natural selection lead to adaptations of populations?
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Natural selection leads to adaptation, that is, to a population dominated by organisms that are anatomically, behaviorally, and physiologically well suited to survive and reproduce in a specific environment. ... Species become extinct because they can no longer survive and reproduce in their altered environment.

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When pink sweet peas were self-pollinated and the seeds were collected and sown, the following flower colors were obtained: Red
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Answer:

c. 1:2:1

The results are consistent with incomplete dominance for this trait, with pink flowers being heterozygous.

Explanation:

If flower color were determined by a gene showing incomplete dominance, the possible genotypes and phenotypes are as follows:

  • RR- red
  • ww - white
  • Rw - pink

If pink sweet peas are self-pollinated, then a cross between two heterozygous individuals is done (Rw x Rw).

<u>From this cross the expected ratios are:</u>

  • 1/4 RR (red)
  • 2/4 Rw (pink)
  • 1/4 ww (white)

So the null hypothesis is that the observed results exhibit a 1:2:1 ratio.

<h3><u>Chi square test</u></h3>

X^{2} = \sum \frac{(Observed - Expected)^2}{Expected}

<u>The observed frequencies were:</u>

  • 34 Red
  • 76 Pink
  • 40 White

Total 150

<u>The expected frequencies for our null hypothesis are:</u>

  • 1/4 x 150 = 37.5 Red
  • 2/4 x 150 = 75 Pink
  • 1/4 x 150 = 37.5 white

X^{2} = \frac{(34- 37.5)^2}{37.5} + \frac{(76- 75)^2}{75} + \frac{(40- 37.5)^2}{37.5}

X^2=0.5067

The degrees of freedom (DF) are calculated as number of phenotypes - 1; in this case DF = 3-1 = 2.

If we look at the Chi square table, for 2 DF and a probability of p0.05, the critical value is 5.991

Our X^2 value of 0.5067 is less than the critical value, so we do not reject the null hypothesis. The results are consistent with incomplete dominance for this trait, with pink flowers being heterozygous.

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Which statement best describes two paths carbon dioxide can take through the carbon cycle?What is a benefit of using renewable e
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