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rjkz [21]
3 years ago
8

Which is the correct formula to find the area of ABC?

Mathematics
2 answers:
Alex777 [14]3 years ago
5 0

Answer:

none of them

Step-by-step explanation:

The area (A) of a triangle is calculated as

A = 0.5 × base × perpendicular height

Here the base is BC and perpendicular height is AD, hence

Area of ΔABC = 0.5 × BC × AD

Neporo4naja [7]3 years ago
4 0

Answer:  C. \text{area of }\triangle ABC=\dfrac{1}{2}\times BC\times AD

Step-by-step explanation:

The common formula is used to find the area of a triangle is

\dfrac{1}{2}\times\text{base}\times\text{altitude}

In the given picture , we have a triangle ABC , in which Altitude (making right angle with base) of triangle = AD with corresponding base = BC

Thus , the area of the triangle will be :

\text{area of }\triangle ABC=\dfrac{1}{2}\times BC\times AD

Therefore , the correct options is

C. \text{area of }\triangle ABC=\dfrac{1}{2}\times BC\times AD

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Find cube root of 175616 ??​
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Answer:

56

Step-by-step explanation:

Cube root of 175616 by prime factorization method is 56

Solution:

To find cube root of 175616 by prime factorization method

A number that must be multiplied by itself three times to equal a given number is called cube root

Prime factorization method:

Prime factorization is a number written as the product of all its prime factors.

In order of finding cube root by prime factorization we use the following steps:

Step I : Obtain the given number

Step II : Resolve it into prime factors.

Step III : Group the factors in 3 in such a way that each number of the group is same

Step IV : Take one factor from each group

Step V : Find the product of the factors obtained in step IV. This product is the required cube root

Prime factorization of 175616:

\text{ prime factors of 175616 } = 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 7 \times 7 \times 7 prime factors of 175616 =2×2×2×2×2×2×2×2×2×7×7×7

Thus we get,

\sqrt[3]{175616} = \sqrt[3]{2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 7 \times 7 \times 7}

3

175616

=

3

2×2×2×2×2×2×2×2×2×7×7×7

Make the groups of 3 of equal numbers

\sqrt[3]{175616} = \sqrt[3]{2 \times 2 \times 2} \times \sqrt[3]{2 \times 2 \times 2 \times } \times \sqrt[3]{2 \times 2 \times 2} \times \sqrt[3]{7 \times 7 \times 7}

3

175616

=

3

2×2×2

×

3

2×2×2×

×

3

2×2×2

×

3

7×7×7

So there are 4 equal groups. So from that group take one factor out

\sqrt[3]{175616} = 2 \times 2 \times 2 \times 7 = 56

3

175616

=2×2×2×7=56

Thus Cube root of 175616 by prime factorization method is 56

please mark me as a brainlist

3 0
3 years ago
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