The value of a28 given a11 = 23 and a15 = −5 is -96
Given:
a11 = 23
a15 = −5
Where,
a1 = first term
d = common difference
a11 = a + 10d = 23
a15 = a + 14d = -5
a + 10d = 23 (1)
a + 10d = 23 (1)a + 14d = -5 (2)
subtract (1) from (2) to eliminate a
14d - 10d = -5 - 23
4d = -28
d = -28 / 4
d = -7
Substitute d = -7 into (1)
a + 10d = 23 (1)
a + 10(-7) = 23
a - 70 = 23
a = 23 + 70
a = 93
So,
a28 = <em>a + 27d</em>
= 93 + 27(-7)
= 93 + -189
= 93 - 189
= -96
Therefore, the value of a28 given <em>a11 = 23</em> and <em>a15 = −5</em> is -96
Learn more about arithmetic sequence:
brainly.com/question/6561461
Answer:
930
Step-by-step explanation:
basically, i' not sure but i think it is 30*31 which is 930.
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Brainliest Please
Answer:
c
Step-by-step explanation:
Since this is a problem of simple interest, then the interest earned will be based always on the principal amount which is 5000. So assuming that, lets also assume that the duration to get interest will be in years since that is the most commonly used duration anyway. So first, let's multiply 5000 with 0.075 to get the interest for the first year. So we will have 375. This means that we will be getting 375 interest every year. We can do trial an error method to get the number of years that will yield us to 6500. Through that, I was able to get 4 years. So 4 times 375 equals 1500 plus the original balance of 5000. It will take 4 years before your balance reaches 6500
