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2 years ago

Help needed asap

Mathematics

1 answer:

ASHA 777 [7]2 years ago

8 0

Answer:

d is the right answer

..................

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For every 6 green apples in an orchard there where 9 red apples what is the ratio of green apples to red apples

MAXImum [283]

Answer:

6:9

or 6 to 9

Step-by-step explanation:

4 0

3 years ago

Two angles of a triangle measure 55° and 20°.

PolarNik [594]

The answer is c because of the fact that if the 2 angles at 55 and 20 that means that you have to add them together and get to 180 for the triangle to be true

4 0

3 years ago

6th-grade math DUE IN 5 MIN

Veseljchak [2.6K]

Answer:

272?

Step-by-step explanation:

10 x 8 = 80

12 x 16 = 192

192 + 80 = 272.

Not sure

3 0

3 years ago

Susan owns a home that is worth $128,318.74, a 2005 truck worth $10,615.00, and has investments that total $4,459.16. Susan owes

allochka39001 [22]

Answer:

Net worth is defined as:

Assets - Liabilities.

Assets are what you own.

Liabilities are what you have to pay.

So, home + truck + investments are assets.

Likewise, mortgage + student loans + credit cards are liabilities.

Doing the math, Susan's net worth is

Assets - Liabilities

$143,392.90 - $98,077.12 =

$45,315.78

Susan's net worth is $45,315.78

Good luck!

5 0

3 years ago

Please help me on this problem

Anna71 [15]

Answer:

The pairs of integer having two real solution for $ax^{2} -6x+c = 0$ are

$a = -4, c = 5$
$a = 1, c = 6$
$a = 2, c = 3$
$a = 3, c = 3$

Step-by-step explanation:

Given

$ax^{2} -6x+c = 0$

Now we will solve the equation by putting all the 6 pairs so we get the following

$-3x^{2} -6x-5 = 0$ for $a = -3 , c=-5$

$-4x^{2} -6x+5 = 0$ for $a = -4 , c=5$

$1x^{2} -6x+6 = 0$ for $a = 1 , c=6$

$2x^{2} -6x+3 = 0$ for $a = 2 , c=3$

$3x^{2} -6x+3 = 0$ for $a = 3 , c=3$

$5x^{2} -6x+4 = 0$ for $a = 5 , c=4$

The above all are Quadratic equations inn general form $ax^{2} +bx+c=0$

where we have a,b and c constant values

So for a real Solution we must have

$Disciminant , b^{2} -4\timesa\timesc \geq 0$

for $a = -3 , c=-5$ we have

$Discriminant =-24$ which is less than 0 ∴ not a real solution.

for $a = -4 , c=5$ we have

$Discriminant = 116$ which is greater than 0 ∴ a real solution.

for $a = 1 , c=6$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 2 , c=3$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 3 , c=3$ we have

$Discriminant =0$ which is equal to 0 ∴ a real solution.

for $a = 5 , c=4$ we have

$Discriminant =-44$ which is less than 0 ∴ not a real solution.

7 0

3 years ago