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2 years ago

Derivative of (2x+9)^3

Mathematics

1 answer:

Gekata [30.6K]2 years ago

3 0

The derivative:

3*(2x+9)^2 * 2

Please let me know if you have questions.

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Find the flow rate through a tube of radius 6 cm, assuming that the velocity of fluid particles at a distance r cm from the cent

vaieri [72.5K]

Answer:

791.68 cm/s

Step-by-step explanation:

The volume flow rate can be interpreted as the integral of fluid velocity over area

$\dot{V} = \int\limits^6_0 {v(r) 2\pi r} \, dr\\\dot{V} = 2\pi\int\limits^6_0 {(25-r^2)r} \, dr\\\dot{V} = 2\pi\int\limits^6_0 {25r-r^3} \, dr\\\\\dot{V} = 2\pi[12.5r^2 - r^4/4]_0^6\\\dot{V} = 2\pi(12.5*6^2 - 6^4/4 - 12.5*0 - 0)\\\dot{V} = 2\pi*126 = 791.68 cm/s$

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3 years ago

Hi people, please if someone can give me a hint with this, l got it but Maths watch doesnt recognise it as 100% right so what is

krek1111 [17]

Answer:

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Step-by-step explanation:

at fifth sentence there is little mistake of pronoun i.e sue there must be she may be by this little mistake that is incorrect.

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3 years ago

Read 2 more answers

What is the answer to this question <br> 8x^2-8

KIM [24]

Answer:

8(x+1)(x-1)

Step-by-step explanation:

I don't know if that is right but that is what I got.

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2 years ago

Put y+7=1/2(x+2) in standard form <br> Standard form: Ax+By=C

My name is Ann [436]

$y+7=\frac{1}{2}(x+2)\ \ \ \ |multiply\ both\ sides\ by\ 2\\\\2y+14=x+2\ \ \ \ |subtract\ x\ and\ 2\ from\ both\ sides\\\\-x+2y+14-2=0\\\\-x+2y+12=0\ \ \ \ \ |change\ signs\\\\\boxed{x-2y-12=0}$

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2 years ago

For the function P(x) = x3 − 9x, at the point (2, −10), find the following. (a) the slope of the tangent to the curve (b) the in

Shalnov [3]

Answer:

3, in both a), b)

Step-by-step explanation:

a) The slope of the line tangent to the curve that passes through the point (2,-10) is equal to the derivative of p at x=2.

Using differentiation rules (power rule and sum rule), the derivative of p(x) for any x is $p'(x)=3x^2-9$ . In particular, the value we are looking for is $p'(2)=3(2^2)-9=12-9=3$ .

If you would like to compute the equation of the tangent line, we can use the point-slope equation to get $y=3(x-2)-10=3x-16$

b) The instantaneus rate of change is also equal to the derivative of P at the point x=2, that is, P'(2). This is equal to $p'(2)=3$ .

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3 years ago