What is 2x+3y•4 plz help me

1 answer:

7 0

Use the distributive property to combine like terms. Since we only have one X value and one y value we need to use the 4. 2x times 4 is 4x. 3y times 4 is 6y. Now the equation can be simplified to 4x plus 6y. We have no more like terms so the equation cannot be simplified any further without more context.

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The correct <br> Answer 1048576

Slav-nsk [51]

Answer:

1048576 is correct!

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Evaluate the summation of negative 2 n minus 3, from n equals 2 to 10..

Alisiya [41]

$\bf \sum\limits_{n=2}^{10}~-2n-3$

so, let's first change the bounds from 1 to 9, so we'll be dropping the indices by 1, in order to do the variable "n".

however, let's use a variable hmmm say "k", where "k" is the value of "n" beginning at 1, thus k = n - 1.

however, if k = n - 1, then k + 1 = n. So let's use those fellows then,

$\bf \sum\limits_{n=2}^{10}~-2n-3\qquad 
\begin{cases}
k=n-1\\
k+1=n
\end{cases}\implies \sum\limits_{k=1}^{9}~-2\stackrel{n}{(k+1)}-3
\\\\\\
\sum\limits_{k=1}^{9}~-2k-2-3\implies \sum\limits_{k=1}^{9}~-2k-5\implies \sum\limits_{k=1}^{9}~-2k-\sum\limits_{k=1}^{9}~5
\\\\\\
-2\sum\limits_{k=1}^{9}~k-\sum\limits_{k=1}^{9}~5\implies -2\left( \cfrac{9(9+1)}{2} \right)\qquad -\qquad (9\cdot 5)
\\\\\\
-2(45)-45\implies -90-45\implies -135$

5 0

3 years ago

Eddie is practicing wind sprints during his summer break. He’s able to run 72 meters in 12 seconds. If d represents distance and

AnnZ [28]

D is distance which is 72 meters
time represents seconds which is 12
so ratio is 12:72
reduce to get 1:6
time over distance would be 1/6
every second Eddie runs 6 meters
so t= d/6
or 6t=d

4 0

3 years ago

"A laboratory tested 73 chicken eggs and found that the mean amount of cholesterol was 230 milligrams with LaTeX: \sigmaσ = 17.4

Scrat [10]

Answer:

The 95% confidence interval for the true mean cholesterol content, μ, of all such eggs is between 226.01 and 233.99 milligrams.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So: