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3 years ago

6

The Store’s wholesale price of a t-shirt is $50. If the markup set by the store is 30%. Calculate the retail price set by the st

ore on the t-shirt. (How much does the store sell the shirt for?)
Wholesale price:
Retail price:
Mark up%:
Work:

1 answer:

DedPeter [7]3 years ago

6 0

Answer:

is 20 dollers cause 5 take away 3 is 20 so 50 take away 30 is 20

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Answer:

3x - 2 = 10

Step-by-step explanation:

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3 years ago

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in 1900, greenville had a population of 4000 people. Greenville's population increased by 100 people each year. Springfield had

jasenka [17]

Answer: year 1948

Step-by-step explanation:

1900 is our t = 0

The population of Greenville can be written as:

G = 4000 + 100*t

the equation for Springfield can be written as:

S = 1000*(1.04)^t

we want to find the value of t that makes S(t) = G(t)

4000 + 100*t = 1000*(1.04)^t

(4000 + 100*t) = 1.04^t

4 + 0.1*t = 1.04^t

now, you can graph both of this equations (left side and right side) and see in wich value of t the graphs intersect eachother, or you also may use different values of t until the values are about the same for both sides, which is the thing i did with the equation:

4 = 1.04^t - 0.1*t

You will find that the correct value is t = 48

So we can assume that in year 1948 the populations will be about the same.

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3 years ago

Different sizes of ribbon need to be cut to go around various shapes for a craft project.

Dima020 [189]

You have five numbers $\sqrt{6},\ 2\dfrac{1}{2},\ -\sqrt{1},\ \dfrac{7}{2}, \ 3.\overline{3}.$

Among them there is one negative number $-\sqrt{1},$ this number is smallest.

Note that

$(\sqrt{6} )^2=6 \text{ and } \left(2\dfrac{1}{2}\right)^2=(2.5)^2=6.25.$

Since 6.25>6, then

$2\dfrac{1}{2}>\sqrt{6}$

and these numbers are less than 3

Note that

$\dfrac{7}{2}=3.5 \text{ and } 3.\overline{3}=3.333333....,$

then $3.3333333...$ and these numbers are greater than 3.

Therefore, the correct order from the smallest to the greatest is:

$-\sqrt{1}, \quad \sqrt{6},\quad 2\dfrac{1}{2},\quad 3.\overline{3}, \quad \dfrac{7}{2}.$

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3 years ago

Use the order of operations to solve. Please write the problem number on your paper and show your work for this problem. Work wi

umka21 [38]

To this question, 533 is the answer

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4 years ago

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I need help with this....

trapecia [35]

Answer:

-512

Step-by-step explanation:

The laws of exponents state that multiplying two exponents together of the same base allows you to add the exponents. Raising an exponent to another power allows you to multiply the exponents. In this case. you have $(-2)^3*((-2^3))^2$ . First, you take the second term, or $((-2^3))^2$ and simplify it. Since you're raising an exponent to another exponent you have $(-2)^(3*2)$ , or $(-2)^6$ . Now, you multiply by $(-2)^3$ . Since they both have the same base, you can add the exponents to get $(-2)^9$ . Since $(-2)^9$ is raised to an odd exponent, you know you're answer is going to be negative. $2^9$ is 512, so that negative would be -512. If you're looking for an expression for this, you can write $(-2)^9$

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3 years ago