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marin [14]
2 years ago
12

3x + y = 5 2x - 2y = -2

Mathematics
2 answers:
zalisa [80]2 years ago
8 0

Answer:

y =5-3x

and

Step-by-step explanation:

<u>First question</u>

Subtract  3 x  from both sides of the equation

Vesnalui [34]2 years ago
7 0

Answer:

Solving the system of equations:

x: 1

y: 2

Step-by-step explanation:

Plug it in to see if it is right, to make sure of course.  Better to be safe than sorry.

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Given that th<span>e coordinates of the vertices of △DEF are D(2, −1) , E(7, −1) , and F(2, −3) and the coordinates of the vertices of △D′E′F′ are D′(0, −1) , E′(−5, −1) , and F′(0, −3) .

Notice that the y-coordinates of the pre-image and that of the image are the same, which means that there is a reflection across the y-axis.

A refrection across the y-axis results in the change in sign of the x-coordinates of the pre-image and the image while the y-coordinate of the image remains the same as that of the pre-image.

A refrection across the y-axis of </span>△DEF with vertices D(2, −1) , E(7, −1) , and F(2, −3) will result in and image with vertices (-2, -1), (-7, -1) and (-2, -3) respectively.

Notice that the x-coordinate of the final image △D′E′F′ with vertices <span>D′(0, −1) , E′(−5, −1) , and F′(0, −3) is 2 units greater than the vertices of the result of recting the pre-image across the y-axis.

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Therefore, </span>the sequence of transformations that maps △DEF to △D′E′F′ are reflection across the y-axis and translation 2 units right.
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Step-by-step explanation:

In,

Question 2 I have already answered,

Q. 3)

<h3><em><u>Given</u></em><em><u> </u></em><em><u>Question</u></em><em><u>:</u></em></h3>

\frac{ {c}^{2} }{d}

<em><u>Given</u></em><em><u> </u></em><em><u>values</u></em><em><u>:</u></em><em><u>-</u></em>

c = 6 , d = 3

<em><u>By</u></em><em><u> </u></em><em><u>putting</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>values</u></em><em><u> </u></em><em><u>in</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>question</u></em><em><u>, </u></em>

\frac{ {6}^{2} }{3}

=  \frac{36}{3}

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