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3 years ago

What is the length of segment AC?

Mathematics

2 answers:

Brut [27]3 years ago

6 0

Making a triangle with line segment AC as the hypotenuse, we see the two legs are 6 and 8 units. Using the Pythagorean theorem, 6^2=36 and 8^2=64. 36+64=100. The square root of 100 is 10, so the length of AC is 10 units. Please give me brainiest. Have a great day.

aev [14]3 years ago

5 0

Answer:

10 units

Step-by-step explanation:

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Step-by-step explanation:

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The merry-go-round at the fair rotates 12 times each minute, and children are 15 feet from the center of the wheel when they are

LiRa [457]

Answer: 16.33 feet/s

Explanation:

1) Data:

a) circular motion
b) revolutions: 12 rpm
c) r = 15 feet
d) v = ?

2) Formulae:

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linear velocity: v = ω × r

3) Solution:

ω = 12 × 2π / 60 s = 0.4π rad / s

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That is the answer.

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olga_2 [115]

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Here is another question 9 hundreds+2000+1<br><br> 0,1,2,9

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Write an equation of the line that passes through the given point and is (a) parallel and (b) perpendicular to the given line.

Harrizon [31]

Answer:

Equation of the line that passes through the given point and is (a) parallel is: $\mathbf{y=-2x+11}$

Equation of the line that passes through the given point and is (b) perpendicular is: $\mathbf{y=\frac{1}{2}x+1}$

Step-by-step explanation:

We need to Write an equation of the line that passes through the given point and is (a) parallel and (b) perpendicular to the given line.

First we will find slope of the line given in graph

The slope can be found using formula: $Slope=\frac{y_2-y_1}{x_2-x_1}$

We have points (1,6) and (2,2)

Slope is:

$Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{2-6}{2-1}\\Slope=\frac{-4}{2}\\Slope=-2$

Part a)

Write an equation of the line that passes through the given point and is (a) parallel

When the lines are parallel, they have same slope. So, slope of required line: m = -2

Using slope m =-2 and point(4,3) we can find y-intercept b

$y=mx+b\\3=-2(4)+b\\3=-8+b\\b=3+8\\b=11$

The equation of line will be:

$y=mx+b\\y=-2x+11$

Equation of the line that passes through the given point and is (a) parallel is: $\mathbf{y=-2x+11}$

Part b)

Write an equation of the line that passes through the given point and is (b) perpendicular

When the lines are perpendicular they have opposite slope. So, slope of required line: m = 1/2

Using slope m =1/2 and point(4,3) we can find y-intercept b

$y=mx+b\\3=\frac{1}{2}(4)+b\\3=2+b\\b=3-2\\b=1$

The equation of line will be:

$y=mx+b\\y=\frac{1}{2}x+1$

Equation of the line that passes through the given point and is (b) perpendicular is: $\mathbf{y=\frac{1}{2}x+1}$

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