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2 years ago

A right triangle has a hypotenuse of length 9 units and includes a 40° angle. What are the lengths of the other two sides?

Mathematics

1 answer:

Hoochie [10]2 years ago

3 0

Answer:

5.79 & 6.89 units

Step-by-step explanation:

Cos(40) =a/h

Cos(40) x 9=a

a=6.89

9^2 - 6.89^2 = a^2

33.5279 =a^2

Square root to get a to be 5.79

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Determine if the following are properties write y or n for each

Paul [167]

Answer:

Answers are below

Step-by-step explanation:

5+1=6 No

78+6=76+8 Yes, commutative property of addition

2x+(3x+4x)=(2x+3x)+4x Yes, associative property of addition

52+(-18)=(-52)+18 No

6+(-6)=0 Yes, identity property of addition

If these answers are correct, please make me Brainliest!

4 0

4 years ago

Show that for the same shear angle, there are two rake angles that give the same cutting ratio.

Yuliya22 [10]

The answer to this question is a equilater triangule

5 0

4 years ago

Eric had a total of 40 nickels and dimes if the total value of the coins is 330 cents, how many nickels and dimes does he have?

kumpel [21]

Answer:

165 of nickels and 165 of dimes

7 0

3 years ago

determining the number of roots of the equation 8x^3+12x^2-50x+135=0 and find also the interval(s) that isolate the roots.Are th

professor190 [17]

Answer:

one negative real root in [-5, -4]; two complex roots
the complex roots cannot be isolated in the same way.

Step-by-step explanation:

A graphing calculator is a wonderful tool for this. It shows the one real root to be near -4.062, so between -5 and -4.

The value of the cubic at x = -5 is -315; at -4 it is +15, so the root is definitely between those values.

The one real root is isolated to being between (-5, -315) and (-4, 15). The complex roots are not isolated.

3 0

3 years ago

What is the simplified base of the function f(x) = One-fourth (Root Index 3 StartRoot 108 EndRoot) Superscript x?

Rainbow [258]

Answer:

The base is: $3 \sqrt[3]{4}$

Step-by-step explanation:

Given

$f(x) = \frac{1}{4}(\sqrt[3]{108})^x$

Required

The base

Expand 108

$f(x) = \frac{1}{4}(\sqrt[3]{3^3 * 4})^x$

Rewrite the exponent as:

$f(x) = \frac{1}{4}(3^3 * 4)^\frac{1}{3}^x$

Expand

$f(x) = \frac{1}{4}(3^3^\frac{1}{3} * 4^\frac{1}{3})^x$

$f(x) = \frac{1}{4}(3 * 4^\frac{1}{3})^x$

Rewrite as:

$f(x) = \frac{1}{4}(3 \sqrt[3]{4})^x$

An exponential function has the following form:

$f(x)=ab^x$

Where

$b \to base$

By comparison:

$b =3 \sqrt[3]{4}$

So, the base is: $3 \sqrt[3]{4}$

4 0

3 years ago