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Ronch [10]
3 years ago
5

if a tree diagram were drawn to determine the number of possible outcomes when choosing one of 5 salads, one of 6 entrees, and o

ne of 9 desserts, how many leaves would there be?
Mathematics
2 answers:
hram777 [196]3 years ago
6 0

Answer:

270

Step-by-step explanation:

Just multiply.

5*6*9=270

Juli2301 [7.4K]3 years ago
6 0

Answer: There would be 270 leaves of a tree diagram.

Step-by-step explanation:

Since we have given that

Number of salads = 5

Number of entrees = 6

Number of desserts = 9

If we draw a tree diagram, we need to find the number of leaves there would be :

So, the number of leaves there would be is given by

5\times 6\times 9\\\\=270

Hence, there would be 270 leaves of a tree diagram.

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PLEASE HELP ME I NEED HELP NOW AND NO ONE IS ANSWERING
Oksanka [162]
All the choices are correct.

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In our base-10 number system, moving a digit one place to the left multiplies its value by 10. Moving it one place to the right multiplies its value by 1/10.

You know already that 1,000 has 10 times the value of 100, and 1/10 the value of 10,000.
4 0
2 years ago
A buoy is 8 km N 60° E of a boat as shown. How far east of<br> the boat is the buoy?
Bumek [7]

Answer:13.86km

Step-by-step explanation: see attachment

6 0
3 years ago
a fair coin is flipped 10 times. what is the probability of getting the same number of heads and tails
Dafna11 [192]

If you flip a coin one time, the probability to get a Head is

p = 1/2

The probability of not getting a head in a single toss is :

q = 1 - 1/2 = 1/2

Thus there is only one unique situation to get the same number of heads and tails : in 10 toss you need to get exactly five heads, it will means that the rest is the tails.

Now using Binomial theorem of probability, the probability of getting exactly x = 5 heads in a total of n = 10 tosses is :

P(X = 5) = \frac{10!}{5!*5!} *(\frac{1}{2})^{5} *(\frac{1}{2})^{5}≈ 0.246

So the probability of that is 24,6 %

Good Luck

3 0
2 years ago
Anya makes a scale drawing of a bug. The scale of the drawing’s length to the actual bug’s length is 2 inches: 1/8 inch. The act
ioda
<h2>Hello!</h2>

The answer is: The Anya's drawing is 6 inches long.

Have a nice day!

<h2>Why?</h2>

To solve this problem, we need to consider the drawing's length with respect to the actual bug's size, so, the scale factor is:

2in:\frac{1}{8}in\\\\2x(in):\frac{3}{4}in

So, how long is Anya's drawing of the bug?

We can find it, using the following equation:

(2x)in=\frac{2in*\frac{3}{4}in}{\frac{1}{8}in}=\frac{\frac{6}{4}in}{\frac{1}{8}in}=\frac{\frac{3}{2}in }{\frac{1}{8}in}\\\\(2x)in=\frac{\frac{3}{2}in }{\frac{1}{8}in }=\frac{3}{2}in*\frac{8}{1}in=12in^{2}\\\\(2x)in=12in^{2} \\\\x=\frac{12in^{2} }{2in}=6in

Hence, the Anya's drawing is 6 inches long.

Have a nice day!

7 0
3 years ago
If a =2+√3, then (a +1/a)
cupoosta [38]

Answer:

8+4√3/2+√3

Step-by-step explanation:

a =2+√3

(a +1/a)

(2+√3+1/2+√3)

(2+√3)^2+1/2+√3

4+4√3+3+1/2+√3

8+4√3/2+√3

4 0
3 years ago
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