Answer:
a) 18 students per teacher
b) 9 students per tutor
c) 7 tutors
Step-by-step explanation:
An arts academy requires there to be 6 teachers for every 108 students and 5 tutors for every 45 students.
a) How many students does the academy have per teacher?
6 teachers = 108 students
1 teacher = x
Cross Multiply.
6x = 108
x = 108/6
x = 18 students per teacher
b) Per tutor?
5 tutor = 45 students
1 tutor = x
Cross Multiply
5x = 45
x = 45/5
x = 9 students
= 9 students per tutor
c) How many tutors does the academy need if it has 63 students?
45 students = 5 tutors
63 students = x
Cross Multiply
45x = 63 × 5
x = 63 × 5/45
x = 7 tutors
Our equation for the area of a rectangle is l x w = A (length times width equals area)
We know that l=w+20 so we can plug this into our equation.
It is now, (w+20) x w =800
We can then solve for w
w^2 +20w =800
We can subtract 800 on each side to get
w^2 +20w - 800 =0
We then factor to get
(w-20)(w+40)=0
This gives us w =20 and w = -40
Width cannot be negative so our width will be 20 feet
Since our length is 20 more than this, then our length will be 40feet
So the dimensions of the rectangle are 20 ft wide by 40 ft long
Ah yes, good ol’ Pythagorean’s theorem.
The hypotenuse is the opposite of the 90 degree angle, the longest side of the triangle.
The legs are opposite of the acute angles
Formula: a^2 + b^2 = c^2
2:
Let’s plug in some values
(6)^2 + (3)^2 = c^2
C = 6.7
The side will be 6.7 units
3)
Let’s plug in some values
(13.3)^2 = (9.7)^2 + (b)^2
(13.3)^2 - (9.7)^2 = b^2
176.89 - 94.09 = b^2
b = 9.1
The side will be 9.1 units
Answer:
32 / 18
Step-by-step explanation:
x2
