Question

In which quadrant would the vertex of f(x+ 3) + 2 be located?

Answer 1

Answer:

QII

Step-by-step explanation:

I'm thinking that this is supposed to be a quadratic and you forgot the ^2 at the end of the (x + 3).  IF this is the case, then the vertex form of a quadratic is

$y=(x-h)^2+k$ where the h inside the parenthesis with the x- indicates side to side movement and the k indicates up and down movement.  Both translations begin at the origin, of course.  The important thing to remember here is that the form "x -" is constant.  So if our quadratic reflects "x - 3", then it is understood to be "x - (3)" and the movement is 3 units to the right.  If the quadratic reflects "x + 3", then it is understood to be "x - (-3)" and the movement is 3 units to the left.  Our quadratic, then, is shifted 3 units to the left of the origin and up 2 units, putting us in QII.

If this is what it appears to be, (x + 3) + 2, then it is x + 5 which is a line that has no vertex (which is why I'm thinking it must be a mistyped quadratic!)