Answer:
0.02275
Step-by-step explanation:
We use the z score formula to solve for this
z-score is given as: z = (x-μ)/σ
where x is the raw score,
μ is the population mean
σ is the population standard deviation
In the above question:
mean of μ=500
a standard deviation of SD=100
raw score x = 700
Hence, z score = (700 - 500)/ 100
= 200/100
= 2
z score = 2
Using the z score table of normal distribution to find the Probability of z = 2
P( x = z)
= P(x = 700)
= P( z = 2)
= 0.97725
P(x>700) = 1 - P(x = 700)
= 1 - 0.97725
= 0.02275
Therefore, the probability of randomly selecting an individual from this population who has an SAT score greater than 700 is 0.02275
