Answer:
Step-by-step explanation:
There are a couple of things to know before we set up the table for this problem. First, we need to remember that if the boat is traveling against the current, that the current is going to slow the boat down; likewise, going with the current will speed the boat up. Second, we need to realize that if the boat's distance against the current is the same as the distance with the current, then the distances in the equations will be set equal to one another.
Set up the table with U (against the current) and D (with the current) on the outside and fill in what we are given:
d = r x t
U
D
This is the table. Now we will fill it in:
d = r x t
U r - 3 x 3
D r + 3 x 1.8
The formula for the distance equation is at the top of the table as d = rt. We already decided that the distances that the boat traveled upstream and downstream were the same so we will set those d values equal to each other, but we first need to get the d value for each row. If distance = rate times time, then for the first row:
d = (r - 3)3 and
d = 3r - 9. For the second row:
d = (r + 3)1.8 and
d = 1.8r + 5.4. Setting them equal to each other:
3r - 9 = 1.8r + 5.4 and
1.2r = 14.4 so
r = 12 mph
Answer:
40 minutes
Step-by-step explanation:
→ Take the total away from the amount he wants left
150 - 30 = 120
→ Divide this by his rate
120 ÷ 3 = 40 minutes
The answer is A. Each element in the domain has to be paired with one element in the range. However, each element in the range be paired with more than one element from the domain.
Answer:
when certain specialized modifications are made to their formulas. The transformations we will study fall into three broad categories: shifts, reflections and scaling, and we will present them in that order. i think this is it sorry if its wrong
Answer:
2 by 4 is the answer have a great time