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maksim [4K]
3 years ago
8

A 4​-ft vertical post casts a 20​-in shadow at the same time a nearby cell phone tower casts a 115​-ft shadow. How tall is the c

ell phone​ tower?
Mathematics
1 answer:
Klio2033 [76]3 years ago
3 0

Answer:

Step-by-step explanation4363 :

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What is the value of triangle in the equation shown? 8 x 4 = (triangle x 7) - (triangle x 3)
GarryVolchara [31]

9514 1404 393

Answer:

  triangle = 8

Step-by-step explanation:

The right side can be factored so that you have ...

  8 x 4 = (triangle x 7) - (triangle x 3)

  8 x 4 = triangle x (7 - 3) . . . . use the distributive property

  8 x 4 = triangle x 4 . . . . . . simplify

  8 = triangle . . . . . . . . . . divide both sides by 4

7 0
3 years ago
Mention the commutativity associative and distributive properties of rational number
evablogger [386]

Answer:

Associative property: a + (b + c), a – (b – c) ≠ (a – b) – c, a × (b × c) = (a × b) × c, and a ÷ (b ÷ c) ≠ (a ÷ b) ÷ c

When a = ½ and b = ¾

Now, for checking a × b = b × a, consider LHS and RHS.

LHS = a × b = ½ × ¾ = ⅜

RHS = b × a = ¾ × ½ = ⅜

Thus, LHS = RHS (Hence proved)

Step-by-step explanation:

6 0
3 years ago
over the summer steven"s tutor told him he needed to complete 15 total workbook pages. he finished 5 workbook pages the first we
Eduardwww [97]
He has 2/3 left to complete.
He did 5 out of 15 which is 5/15 or 1/3. Therefore he has 1-1/3 or 2/3 left.
7 0
3 years ago
Please help me!!!!! :)
lora16 [44]

6 / (x + 6) = 10/15

10(x+6) = 90

10x + 60 = 90

10x = 30

x = 3

7 0
3 years ago
a small rocket is shot from the edge of a cliff suppose that after t seconds the rocket is y meters above the cliff where y=30t-
Natalka [10]

Answer:

Greatest height: 45 meters

Time for greatest height: 3 seconds

Height after 5 seconds: 25 meters above the cliff

Time for height of 40 meters: 7.123 seconds

Height after 7 seconds: -35 meters (35 meters below the cliff)

Step-by-step explanation:

to find the maximum height, we need to calculate the derivative of y in relation to t and then find when dy/dt = 0:

dy/dt = 30 - 10t = 0

10t = 30

t = 3 seconds

In this time, the height is:

y = 30*3 - 5*3^2 = 45 meters

After 5 seconds, the height is:

y = 30*5 - 5*5^2 = 25 meters

The time for the height of 40 meters is:

40 = 30t - 5t^2

t^2 - 6t - 8 = 0

Using Bhaskara's formula, we have:

Delta = 6^2 + 4*8 = 68

sqrt(Delta) = 8.246

t1 = (6 + 8.246) / 2 = 7.123 seconds

t2 = (6 - 8.246) / 2 = -1.123 seconds (negative value for time is not valid)

So the time when the rocket reaches 40 meters is 7.123 seconds

After 7 seconds, the height is:

y = 30*7 - 5*7^2 = -35 meters

The rocket will be 35 meters below the cliff.

5 0
3 years ago
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