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maw [93]
3 years ago
12

Find the 25th term of the arithmetic sequence when a1 = -14 and d = -5

Mathematics
2 answers:
aniked [119]3 years ago
7 0

Answer:easy

Step-by-step explanation:

25 terms=a+24d

=-14+24×(-5)

=-14-120

=-134

Lyrx [107]3 years ago
6 0

Answer:

-106

Step-by-step explanation:

the arithmetic equation is

an=a1+(n-1)d

a(25th)=14+(25-1)(-5)

14+(24)(-5)

14+(-120)

14-120

a25=-106

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<u>Long Division:</u>

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       -  <u>(6x²  -  3x)</u>   ↓

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<u>Remainder Theorem:</u>

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f(x) = 6x² + 11x - 3

f(\frac{1}{2}) = 6(\frac{1}{2})² + 11(\frac{1}{2}) - 3

      = 6(\frac{1}{4}) + \frac{11}{2} - 3

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      = \frac{8}{2}

      = 4

                                     

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