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2 years ago

What is the answer of 3x-3=12

Mathematics

2 answers:

Radda [10]2 years ago

5 0

Answer:

x=5

Step-by-step explanation:

Pull out like factors :

3x - 15 = 3 • (x - 5)

Equation at the end of step 1 :

Step 2 :

Equations which are never true :

2.1 Solve : 3 = 0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation :

2.2 Solve : x-5 = 0

Add 5 to both sides of the equation :

x = 5

One solution was found :

x = 5

madam [21]2 years ago

4 0

My answer is 9 because 3x-3=12

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Im lost please help me

zepelin [54]

Let C = the Chinese books.
Let E = the English language books.

C = 4/5 E

E - 300 = C - 180 Notice how you get this equation. You take 300 away from the English books and 180 from the Chinese and according to the question, you get an equal number of both. Put c = 4/5E into the second equation.

E - 300 = 4/5 E - 180 Add 300 to both sides.
E = 4/5 E - 180 + 300
E = 4/5 E + 120 Now subtract 4/5 E from both sidies.
E - 4/5 E = 120
1/5 E = 120 Now multiply by 5
E = 120 * 5
E = 600

So the number of books are
600 written in English
4/5 of 600 = 2400 /5 = 480 Chinese books.

English 600
Chinese 480

6 0

3 years ago

The function f(x) = x2 + 22x + 58 is translated 4 units to the right and 16 units up. What is the vertex form of the new functio

kap26 [50]

Answer:

The new function is (x + 7)² - 47 ⇒ the 3rd answer

Step-by-step explanation:

* Lets put the function f(x) in the vertex form at first and then make

the translation

∵ The general form of the quadratic function is

f(x) = ax² + bx + c

∵ The x-coordinate of the vertex of the function is -b/2a

∵ The y-coordinate of the vertex of the function is f(-b/2a)

- Lets find a , b from the function two find the vertex point

∵ f(x) = x² + 22x + 58

∴ a = 1 , b = 22 , c = 58

∵ x-coordinate of the vertex = -b/2a

∴ x-coordinate of the vertex = -22/2(1) = -11

∵ y-coordinate of the vertex = f(-11)

∴ f(-11) = (-11)² + 22(-11) + 58 = 121 - 242 + 58 = -63

∴ The vertex point is (-11 , -63)

- The vertex form of the quadratic function is f(x) = (x - h)² + k , where

(h , k) are the coordinates of the vertex point

∵ The vertex point is (-11 , -63)

∴ h = -11 , k = -63

∴ f(x) = (x - -11)² + -63

∴ f(x) = (x + 11)² - 63

* lets revise the rules of the translation

- If the function f(x) translated horizontally to the right

by m units, then the new function g(x) = f(x - m)

- If the function f(x) translated horizontally to the left

by m units, then the new function g(x) = f(x + m)

- If the function f(x) translated vertically up

by n units, then the new function g(x) = f(x) + n

- If the function f(x) translated vertically down

by n units, then the new function g(x) = f(x) – n

∵ f(x) will translate 4 units to the right

∴ m = 4

∵ f(x) ⇒ f(x - m)

∴ (x + 11)² ⇒ (x + 11 - 4)² = (x + 7)²

∵f(x) will translate 16 units up

∴ -63 will add by 16

∴ n = 16

∴ f(x) ⇒ f(x) + n

∵ -63 + 16 = -47

∴ The new function is (x + 7)² - 47

5 0

3 years ago

Read 2 more answers

The polynomial function y = x3 -3x2 + 16x - 48 has only one non-repeated x-intercept. What do you know about the complex zeros o

earnstyle [38]

• First way to solve:
We'll manipulate the expression of the equation:

$y=x^3-3x^2+16x-48\\\\ y=x^2(x-3)+16(x-3)\\\\ y=(x-3)(x^2+16)$

If we have y=0:

$x-3=0~~~or~~~x^2+16=0\\\\ x=3~~~or~~~x^2=-16\\\\ x=3~~~or~~~x=\pm\sqrt{-16}\\\\ x=3~~~or~~~x=\pm4i$

Then, the function has one real zero (x=3) and two imaginary zeros (4i and -4i).

Answer: B

• Second way to solve:

The degree of the function is 3. So, the function has 3 complex zeros.

Since the coefficients of the function are reals, the imaginary roots are in a even number (a imaginary number and its conjugated)

The function "has only one non-repeated x-intercept", then there is only one real zero.

The number of zeros is 3 and there is 1 real zero. So, there are 2 imaginary zeros.

Answer: B.

3 0

2 years ago

What is the absolute value of -3+4i

Pavlova-9 [17]

$|-3+4i|=\sqrt{(-3)^2+4^2}=\sqrt{25}=5$