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julsineya [31]
3 years ago
5

Angela has 63 eggplants in 21 rows of her eggplant garden.

Mathematics
1 answer:
Lorico [155]3 years ago
6 0

Answer:

A. 27

Step-by-step explanation:

21 x 3 = 63

9 x 3 = 27

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13. A jeweller bought an engagement ring for €1200 and
maks197457 [2]

Answer:

CP of ring = 1200

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Profit amount = 15% 0f 1200 = 180

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Which equation represents a line parallel to the line shown on the graph? On a coordinate plane, a line goes through (0, 8) and
dezoksy [38]

Answer:

  • B) y = negative 4 x + three

Step-by-step explanation:

<u>Find the slope of the line that goes through (0, 8) and (2, 0):</u>

  • m = (y₂ - y₁)/(x₂ - x₁)
  • m = (0 - 8) / (2 - 0) = -8/2 = -4

Parallel lines have equal slopes.

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did it show the number line she threw?

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3 years ago
businessText message users receive or send an average of 62.7 text messages per day. How many text messages does a text message
KiRa [710]

Answer:

(a) The probability that a text message user receives or sends three messages per hour is 0.2180.

(b) The probability that a text message user receives or sends more than three messages per hour is 0.2667.

Step-by-step explanation:

Let <em>X</em> = number of text messages receive or send in an hour.

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em>.

It is provided that users receive or send 62.7 text messages in 24 hours.

Then the average number of text messages received or sent in an hour is: \lambda=\frac{62.7}{24}= 2.6125.

The probability of a random variable can be computed using the formula:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0, 1, 2, 3, ...

(a)

Compute the probability that a text message user receives or sends three messages per hour as follows:

P(X=3)=\frac{e^{-2.6125}(2.6125)^{3}}{3!} =0.21798\approx0.2180

Thus, the probability that a text message user receives or sends three messages per hour is 0.2180.

(b)

Compute the probability that a text message user receives or sends more than three messages per hour as follows:

P (X > 3) = 1 - P (X ≤ 3)

              = 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

             =1-\frac{e^{-2.6125}(2.6125)^{0}}{0!}-\frac{e^{-2.6125}(2.6125)^{1}}{1!}-\frac{e^{-2.6125}(2.6125)^{2}}{2!}-\frac{e^{-2.6125}(2.6125)^{3}}{3!}\\=1-0.0734-0.1916-0.2503-0.2180\\=0.2667

Thus, the probability that a text message user receives or sends more than three messages per hour is 0.2667.

6 0
3 years ago
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