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jek_recluse [69]
3 years ago
14

You own 5 pairs of jeans and want to take 2 of them with you on vacation. In how many ways can you choose 2 pairs of jeans?

Mathematics
1 answer:
balu736 [363]3 years ago
6 0

the answer would be D

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 What are the numbers from least to greatest 6,0,-9,-4.2
Vadim26 [7]

Answer:

(-9), (-4.2), 0, 6

Step-by-step explanation:

Come on

Negative the highest number is first, then zero, positive lowest number is first

you get the point

4 0
2 years ago
A right Triangle XYZ has Vertices X(−2, −1) and Y(1, 1) and a right angle at Vertex Z.
Bingel [31]

Answer:

x(1,4)  Y(2,3)  and Z(5,y)

Step-by-step explanation:

5 0
2 years ago
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Drag the correct factors to the expression. Not all factors will be used. Use synthetic division to find all the factors of this
fiasKO [112]

The factors are therefore;  (4x – 3), (x + 3) and (x – 1)

<h3>What is a polynomial?</h3>

A polynomial is is a function that contains an algebraic term which is raised to a particular power.

  • If it is raised to power 1 it is linear
  • If it is raised to power 2 it is quadratic
  • If its is raised to power 3 it is cubic
  • If it i raised to power 3 it is quartic

Now we have;

4x³ + 5x² – 18x + 9

Thus we can write;

4x³ – 3x² + 8x² – 6x – 12x + 9

Using the factors;

x²(4x – 3) + 2x(4x² – 3) – 3(4x – 3)

Therefore;

(4x – 3)(x² + 2x– 3)

(4x – 3)(x² + 3x – x – 3)

(4x – 3)(x + 3)(x – 1)

The factors are therefore;  (4x – 3), (x + 3) and (x – 1)

Learn more about polynomials:brainly.com/question/21334281

#SPJ1

3 0
1 year ago
Suppose that a cyclist began a 476
mojhsa [17]
Well, we know the cyclist left the western part going eastwards, at the same time the car left the eastern part going westwards

the distance between them is 476 miles, and they met 8.5hrs later

let's say after 8.5hrs, the cyclist has travelled "d" miles, whilst the car has travelled the slack, or 476-d, in the same 8.5hrs

we know the rate of the car is faster... so if the cyclist rate is say "r", then the car's rate is r+33.2

thus    \bf \begin{array}{lccclll}&#10;&distance&rate&time\\&#10;&-----&-----&-----\\&#10;\textit{eastbound cyclist}&d&r&8.5\\&#10;\textit{westbound car}&476-d&r+33.2&8.5&#10;\end{array}\\\\&#10;-----------------------------\\\\&#10;\begin{cases}&#10;\boxed{d}=8.5r\\\\&#10;476-d=(r+33.2)8.5\\&#10;----------\\&#10;476-\boxed{8.5r}=(r+33.2)8.5&#10;\end{cases}

solve for "r", to see how fast the cyclist was going

what about the car? well, the car's rate is r + 33.2
6 0
3 years ago
Please helpppppp tysm Have a wonderful day.
pav-90 [236]

Answer:

418.4

Step-by-step explanation:

5 0
2 years ago
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