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lisov135 [29]
3 years ago
13

A produce manager needs to order 76 bundles of asparagus for a busy holiday weekend. The supplier received the order, and each o

f his cases has 12 bundles. How many cases of asparagus will he deliver? A. 62⁄3 B. 65⁄6 C. 61⁄3 D. 53⁄4
Mathematics
1 answer:
mixer [17]3 years ago
3 0

Answer: Option 'C' is correct.

Explanation:

Since we have given that

Number of bundles of asparagus for a busy holiday weekend he needs to order = 76

Number of bundles in his each case = 12

Since we need to find the number of cases of asparagus he will deliver for this we'll use the division operation .

So, number of cases of asparagus he will deliver is given by

\frac{76}{12}=6\frac{4}{12}=6\frac{1}{3}

So, Option 'C' is correct.

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Answer:

$7.7

Step-by-step explanation:

Step one:

given data

total money = $175

He buys 4 shirts for $24 each= 24*4= $96

The shirts are discounted 20%

= 96- 0.2*96= 96-19.2= $76.8

2 pairs of shorts for $18 each= $36

2 pairs of pants for $22.50 each= $45

Total cost = $157.8

tax= 6%

total expenses

= 157.8+ 0.06*157.8

=157.8+9.468

=$167.268

The balance is

= 175-167.268

=$7.7

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A factory has four machines that produce the same item. Machines 1 and 2 each produce 20% of the total output, while machines 3
andrezito [222]

Answer:

The answers are a. 0.27 b. 0.2 c. 0.2 d. 0.3 e. 0.3 f. 1

Step-by-step explanation:

Total output = 100% = 1

Total defective = 6% + 5% + 8% + 8% = 27% = 27

a. Prob of defective item = total defective/total output

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= 0.27

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c. Prob of item defective from machine2 = 5/27 = 0.1852

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d. Prob of de defective from machine 3 = 8/27 = 0.2963

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e. Prob of defective from machine 4

= 8/27 = 0.2963

~ 0.3

f. Sum of prob from b-e

0.2 + 0.2 + 0.3 + 0.3

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I hope this helps you

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