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professor190 [17]
3 years ago
12

what is the area of a regular hexagon ABCDEF if ab is 2 units? Express your answer in simplest radical form.

Mathematics
1 answer:
Alchen [17]3 years ago
8 0

Find the area of a regular hexagon with an apothem 10.4 yards long and a side 12 yards long. Round your answer to the nearest tenth.

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If there is no seasonal effect on human births, we would expect equal numbers of children to be born in each season (winter, spr
Minchanka [31]

Answer:

Step-by-step explanation:

Hello!

Given the variable of interest:

X: Number of births in each season of the year, categorized: W: Winter, Sp: Spring, Su: Summer and F: Fall

The objective is to test if there is no seasonal effect on human births. If this is true, then you would expect the proportion of births to be the same through all seasons. This means that, theoretically, you could expect that P(W)=P(Sp)=P(Su)=P(F)=1/4

To test this out a student made a census in her class and obtained the following observations:

n= 120 students surveyed

25 were born in Winter

35 were born in Spring

32 were born in Summer

28 were born in Fall

The appropriate statistic analysis to test the student's presumption is a Goodness to Fit Chi-Square test, with hypotheses:

H_{0}: P_{W}=P_{Sp}=P_{Su}=P_{F}=1/4

H₁: At least one of the proportions is different from the others.

a) To calculate the expected frequency for each category you have to use the following formula Ei= n*Pi

Where Pi represents the expected proportion for the i-category.

In this particular case, the expected proportion for all categories is the same so the expected frequency will also be the same:

E_{W}= n*P_{W}= 120*1/4= 30\\E_{Sp}= n*P_{Sp}= 120*1/4=30\\E_{Su}= n*P_{Su}= 120*1/4=30\\E_{F}= n*P_{F}= 120*1/4=30

b)

X²=∑\frac{(Oi-Ei)^2}{Ei}~X^2_{k-1}

X^2_{H_0}= \frac{(25-30)^2}{30} + \frac{(35-30)^2}{30} + \frac{(32-30)^2}{30} + \frac{(28-30)^2}{30} = 1.93

c)

The statistic for this test has k-1 degrees of freedom, where k represents the number of categories of the variable. In this case, the statistic has 4-1=3 degrees of freedom.

d)

The rejection region for the Goodnes to Fit test is <u>always</u> one-tailed to the right, wich means that you'll reject the null hypothesis to big values of X²:

X^2_{k-1;1-\alpha }= X^2_{3;0.95}= 7.815

The decision rule is:

If X^2_{H_0} ≥ 7.815, reject the null hypothesis

If X^2_{H_0} < 7.815, do not reject the null hypothesis

e)

X^2_{H_0}= 1.93 is less than the critical value 7.815, so the decision is to not reject the null hypothesis.

Using a 5% level of significance, there is no significant evidence to reject the null hypothesis. Then you can conclude that there is no seasonal effect on human birth, i.e. the expected birth proportions are the same through all seasons.

I hope this helps!

5 0
3 years ago
Sebuah LSM akan mengirim 5 utusan untuk mengikuti suatu konferensi. Kelima utusan tersebut terdiri dari 3 wanita dan 2 pria. Kel
jolli1 [7]
Peking itis an until mengikutu dusty konferensi Klein’s itis an.
7 0
3 years ago
Two angles are supplementary. One angle is 36 degrees bigger than the other. What is the measure of the bigger angle
Lorico [155]

let the other angle be x degree

bigger angle = x +36°

According to the question,

x+36° + x° = 180°

=> 2x = 180–36

=> x = 144/2

=> x = 72°

Measure of the bigger angle = x + 36

= 72° + 36°

= 108°

5 0
3 years ago
HELP TIMED BRAINLIST QUICK
lorasvet [3.4K]

Answer:

12 x^9 + 15 x^8 - 8 x^6 - 10 x^5 = A.) is the answer

Step-by-step explanation:

Expand the following:

x^4 (3 x^3 - 2) (4 x^2 + 5 x)

Hint: | Multiply 3 x^3 - 2 and 4 x^2 + 5 x together using FOIL.

(3 x^3 - 2) (4 x^2 + 5 x) = (3 x^3) (4 x^2) + (3 x^3) (5 x) + (-2) (4 x^2) + (-2) (5 x) = 12 x^5 + 15 x^4 - 8 x^2 - 10 x = 12 x^5 + 15 x^4 - 8 x^2 - 10 x:

x^4 12 x^5 + 15 x^4 - 8 x^2 - 10 x

Hint: | Distribute x^4 over 12 x^5 + 15 x^4 - 8 x^2 - 10 x.

x^4 (12 x^5 + 15 x^4 - 8 x^2 - 10 x) = x^4 (12 x^5) + x^4 (15 x^4) + x^4 (-8 x^2) + x^4 (-10 x):

12 x^4 x^5 + 15 x^4 x^4 - 8 x^4 x^2 - 10 x^4 x

Hint: | Combine products of like terms.

x^4 (-10) x = x^(4 + 1) (-10):

12 x^4 x^5 + 15 x^4 x^4 - 8 x^4 x^2 + -10 x^5

Hint: | Evaluate 4 + 1.

4 + 1 = 5:

12 x^4 x^5 + 15 x^4 x^4 - 8 x^4 x^2 - 10 x^5

Hint: | Combine products of like terms.

x^4 (-8) x^2 = x^(4 + 2) (-8):

12 x^4 x^5 + 15 x^4 x^4 + -8 x^6 - 10 x^5

Hint: | Evaluate 4 + 2.

4 + 2 = 6:

12 x^4 x^5 + 15 x^4 x^4 - 8 x^6 - 10 x^5

Hint: | Combine products of like terms.

x^4×15 x^4 = 15 x^8:

12 x^4 x^5 + 15 x^8 - 8 x^6 - 10 x^5

Hint: | Combine products of like terms.

x^4×12 x^5 = x^(4 + 5)×12:

12 x^9 + 15 x^8 - 8 x^6 - 10 x^5

Hint: | Evaluate 4 + 5.

4 + 5 = 9:

Answer: 12 x^9 + 15 x^8 - 8 x^6 - 10 x^5

7 0
3 years ago
Read 2 more answers
I need help!!!!!!! I will give brainliest!!!!
s2008m [1.1K]

Answer:

You would need to know the area and the base so then

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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