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coldgirl [10]
3 years ago
15

Lily is using dark power crystals to raise an army of zombies. Each crystal can raise 9 zombies. How many crystals does Lily nee

d to raise 6,174 zombies?
Mathematics
1 answer:
zvonat [6]3 years ago
7 0

Answer:

686 crystals.

Step-by-step explanation:

You can set up an algebraic equation to find the answer.

Let x represent the number of crystals Lily uses.

The question is asking how many crystals it will take to raise 6,174 zombies, when each crystal raises 9.

9x = 6174

x = 6174 / 9

x = 686

That means it will take Lily 686 dark power crystals to raise 6,174. That's a lot of dark power!

Hope this helps!

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I need help asap ! this is 6th grade math surface area .
faltersainse [42]

Answer:

<h2>S.A. = 62</h2>

Step-by-step explanation:

We have:

two rectangles 2 × 3

two rectangles 3 × 5

two rectangles 2 × 5

Calculate the areas:

A₁ = (2)(3) = 6

A₂ = (3)(5) = 15

A₃ = (2)(5) = 10

The Surface Area:

S.A. = 2A₁ + 2A₂ + 2A₃

S.A. = (2)(6) + (2)(15) + (2)(10) = 12 + 30 + 20 = 62

8 0
3 years ago
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Is that a question or answer? If it's a question that's the right answer.
3 0
3 years ago
A student repeatedly measures the mass of an object using a mechanical balance and gets the following values: 560 g, 562 g, 556
MrRissso [65]

Answer: 2.76 g

Step-by-step explanation:

The formula to find the standard deviation:-

\sigma=\sqrt{\dfrac{\sum(x_i-\overline{x})^2}{n}}

The given data values : 560 g, 562 g, 556 g, 558 g, 560 g, 556 g, 559 g, 561 g, 565 g, 563 g.

Then,  \overline{x}=\dfrac{\sum_{i=1}^{10} x_i}{n}\\\\\Rightarrow\ \overline{x}=\dfrac{560+562+556+558+560+556+559+561+565+563}{10}\\\\\Rightarrow\ \overline{x}=\dfrac{5600}{10}=560

Now, \sum_{i=1}^{10}(x_i-\overline{x})^2=0^2+2^2+(-4)^2+(-2)^2+0^2+(-4)^2+(-1)^2+1^2+5^2+3^2\\\\\Rightarrow\ \sum_{i=1}^{10}(x_i-\overline{x})^2=76

Then, \sigma=\sqrt{\dfrac{76}{10}}=\sqrt{7.6}=2.76

Hence, the  standard deviation of his measurements = 2.76 g

6 0
3 years ago
(b) Find the equation of the straight line which passes through 81 +88 (i) the point (3, 2) and makes an intercept on the x-axis
ad-work [718]

3x+y=0 and x+2y=7

i)

a= intercept on x axis

b= intercept on y axis

from the question

a=2b

x/2b+ y/b=1

x+2y=2b

since it passes through the point (3,2)

then 3+4=2b

7/2=b

x+2y=7     putting the value of b

ii) given b =3a

then x/a+ y/ 3a =1

3x+y=3a

it passes through ( -1,3) then

-3+3=3a

a=0

3x+y=0

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6 0
1 year ago
Choose whether it's always, sometimes, never 
Keith_Richards [23]

Answer: An integer added to an integer is an integer, this statement is always true. A polynomial subtracted from a polynomial is a polynomial, this statement is always true. A polynomial divided by a polynomial is a polynomial, this statement is sometimes true. A polynomial multiplied by a polynomial is a polynomial, this statement is always true.

Explanation:

1)

The closure property of integer states that the addition, subtraction and multiplication is integers is always an integer.

If a\in Z\text{ and }b\in Z, then a+b\in Z.

Therefore, an integer added to an integer is an integer, this statement is always true.

2)

A polynomial is in the form of,

p(x)=a_nx^n+a_{n-1}x^{x-1}+...+a_1x+a_0

Where a_n,a_{n-1},...,a_1,a_0 are constant coefficient.

When we subtract the two polynomial then the resultant is also a polynomial form.

Therefore, a polynomial subtracted from a polynomial is a polynomial, this statement is always true.

3)

If a polynomial divided by a polynomial  then it may or may not be a polynomial.

If the degree of numerator polynomial is higher than the degree of denominator polynomial then it may be a polynomial.

For example:

f(x)=x^2-2x+5x-10 \text{ and } g(x)=x-2

Then \frac{f(x)}{g(x)}=x^2+5, which a polynomial.

If the degree of numerator polynomial is less than the degree of denominator polynomial then it is a rational function.

For example:

f(x)=x^2-2x+5x-10 \text{ and } g(x)=x-2

Then \frac{g(x)}{f(x)}=\frac{1}{x^2+5}, which a not a polynomial.

Therefore, a polynomial divided by a polynomial is a polynomial, this statement is sometimes true.

4)

As we know a polynomial is in the form of,

p(x)=a_nx^n+a_{n-1}x^{x-1}+...+a_1x+a_0

Where a_n,a_{n-1},...,a_1,a_0 are constant coefficient.

When we multiply the two polynomial, the degree of the resultand function is addition of degree of both polyminals and the resultant is also a polynomial form.

Therefore, a polynomial subtracted from a polynomial is a polynomial, this statement is always true.

3 0
3 years ago
Read 2 more answers
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