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allochka39001 [22]
4 years ago
5

Write a polynomial function p(x) with x-intercepts at -1,4, and -5

Mathematics
1 answer:
KATRIN_1 [288]4 years ago
6 0

Answer:

x^3 + 2x^2 - 19x - 20

Step-by-step explanation:

Just use factored form to make them zeros, therefore making them x intercepts.

-1 --> x + 1

4 --> x - 4

-5 --> x + 5

(x + 1)(x - 4)(x + 5) = 0

Now multiply this out with a Punnett square.

After that, the result is...

x^3 + 2x^2 - 19x - 20

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Step-by-step explanation:

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hodyreva [135]

Answer:

C. \frac{27}{225}=\frac{b}{100}

Step-by-step explanation:

To find the number of black ribbons one would have subtract the amount of red ribbons from the total number of ribbons. Then one would have to express it as a proportion. Part over whole equals percent over 100. The number of black ribbons over total ribbons equals "b" over 100.

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When the two equations are graphed on a coordinate plane, they intersect at two points.
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Answer:

(0,4) and (-2,0)

Step-by-step explanation:

y=3x²+4x+4

y = -2x +4

3x²+4x+4 = - 2x +4

3x²+6x=0

3x(x+2)=0

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3 0
3 years ago
What is the area of the rectangle? shoe your work! do not round anything until the very end and round your final answer to the t
weeeeeb [17]

Answer:

The area of the rectangle is 42 units^2

Step-by-step explanation:

we know that

The area of rectangle is equal to

A=LW

In this problem

AB=DC

BC=AD

see the attached figure with letters to better understand the problem

we have that

L=BC\\W=AB

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have the points

A(2,-1),B(5,2),C(12,-5),D(9,-8)

<em>Find out the distance BC</em>

we have

B(5,2),C(12,-5)

substitute in the formula

d=\sqrt{(-5-2)^{2}+(12-5)^{2}}

d=\sqrt{(-7)^{2}+(7)^{2}}

d_B_C=\sqrt{98}\ units

<em>Find out the distance AB</em>

we have

A(2,-1),B(5,2)

substitute in the formula

d=\sqrt{(2+1)^{2}+(5-2)^{2}}

d=\sqrt{(3)^{2}+(3)^{2}}

d_A_B=\sqrt{18}\ units

<em>Find out the area</em>

A=(L)(W)

we have

L=d_B_C=\sqrt{98}\ units

W=d_A_B=\sqrt{18}\ units

substitute

A=(\sqrt{98})(\sqrt{18})=42.0\ units^2

4 0
3 years ago
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