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sashaice [31]
3 years ago
13

How do i factor 2x^2 - 16x + 32 ?

Mathematics
1 answer:
lora16 [44]3 years ago
4 0
2x^2 - 16x + 32 = 2x^2 - 8x - 8x + 32 = 2x(x - 4) - 8(x - 4) = (2x - 8)(x - 4)
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Jen classifies the number 4.567 as an irrational number because it does not repeat. Is Jen correct? Explain.
lilavasa [31]

Answer:

Yes

Step-by-step explanation:

That number is irrational because it does not repeat and rational number repeats

3 0
3 years ago
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X2 +10x=39 , how do i solve or whats the answer
stealth61 [152]

Answer:

x = 3,-13 :)

Step-by-step explanation:

hope this helps plz brainiest

4 0
3 years ago
What are the coordinates of P' if P (-5,-4) undergoes a dilation, centered at the origin, with a scale factor of K=2?
Margaret [11]

Answer:

P' = (-10,-8)

Step-by-step explanation:

Given

P = (-5,-4)

k =2

Required

Determine the image P'

P' is calculated by multiplying P and k.

i.e.

P' = P * k

This gives:

P' = (-5,-4) * 2

P' = (-5* 2,-4* 2)

P' = (-10,-8)

<em>Hence, the image P' after dilating P is (-10,-8)</em>

7 0
3 years ago
Wayne has 303 marbles if he gives away 123 of the marbles equally to 3 friends about how many marbles will wayne give each frien
Lera25 [3.4K]

Answer:

Each friend receives 41 marbles, Wayne has 180 marbles left.  

Step-by-step explanation:

Wayne starts with 303 marbles total.  If he decides to give 123 of his marbles away to his friends, we can subtract this amount from his total to get how many he has left:

303 - 123 = 180 marbles left

We also want to know how many marbles each of his three friends receives.  Since he wants to split them equally, we need to divide the number he is giving away by 3:

123 ÷ 3 = 41 marbles a piece to each friend

6 0
3 years ago
Read 2 more answers
Suppose you roll a fair six-sided die. Then you roll a fair eight-sided die. Match each probability to its correct value.
Anna35 [415]

Answer:

A) matches \frac{5}{48}

B) matches \frac{1}{12}

C) matches \frac{1}{4}

D) matches \frac{1}{8}

E) matches \frac{5}{16}

Step-by-step explanation:

The sample space for the roll of six sided die and eight sided die:

(1,1),  (1,2),  (1,3),  (1,4),  (1,5),  (1,6),  (1,7),  (1,8)

(2,1), (2,2), (2,3), (2,4), (2,5), (2,6), (2,7), (2,8)

(3,1), (3,2), (3,3), (3,4), (3,5), (3,6), (3,7), (3,8)

(4,1), (4,2), (4,3), (4,4), (4,5), (4,6), (4,7), (4,8)

(5,1), (5,2), (5,3), (5,4), (5,5), (5,6), (5,7), (5,8)

(6,1), (6,2), (6,3), (6,4), (6,5), (6,6), (6,7), (6,8)

Therefore, the total number of outcomes (Sample space) = 48

Probability  =\frac{Number Of Ways Event Can Occur}{Sample Space}

A) The possible ways of obtaining both numbers are odd numbers and their product is greater than 10 are: (3,5), (3,7), (5,3), (5,5), (5,7)

Total number of possible ways = 5

Sample space = 48

The probability that both numbers are odd numbers and their product is greater than 10:

                                 =\frac{5}{48}

B) The possible ways of obtaining second number is twice the first number are: (1,2), (2,4), (3,6), (4,8)

Total number of possible ways = 4

Sample space = 48

The probability that the second number is twice the first number:                  

                       =\frac{4}{48}  =\frac{1}{12}

C) The possible ways of getting numbers whose sum is a multiple of 4 are: (1,3), (1,7), (2,2), (2,6), (3,1), (3,5), (4,4), (4,8), (5,3), (5,7), (6,2), (6,6)

Total number of possible ways = 12

Sample space = 48

The probability of getting numbers whose sum is a multiple of 4:

                       =\frac{12}{48}  =\frac{1}{4}

D) The possible ways of getting the sum of the two numbers is greater than 11 are: (4,8), (5,7), (5,8), (6,6), (6,7), (6,8)

Total number of possible ways = 6

Sample space = 48

the probability that the sum of the two numbers is greater than 11:

                      =\frac{6}{48}  =\frac{1}{8}

E) The possible ways of getting the second number rolled is less than the first number are: (1,2), (1,3), (1,4), (1,5), (1,6), (2,3), (2,4), (2,5), (2,6), (3,4), (3,5), (3,6), (4,5), (4,6), (5,6)

Total number of possible ways = 15

Sample space = 48

The probability that the second number rolled is less than the first number:

                 =\frac{15}{48}  =\frac{5}{16}

                 

5 0
3 years ago
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