The answer is absolute dictator
Well it's 4 time the radius, so 4r
And it's 3 less than that, so
4r - 3 is the height
Answer:
Step-by-step explanation:
- If f(x) is in th form of f(x)=g(x)-h(x) then f'(x)=g'(x) - h'(x)
- When f(x)=z(g(x)) then f'(x)= z'(g(x))g'(x) (called as chain rule)
<u>using these information</u>:
g(x)=ln2x then g'(x)=
h(x)=In(3x - 1) then h'(x)=![\frac{(3x-1)'}{3x-1} =\frac{3}{3x-1}f'(x)=g'(x) - h'(x) =[tex]\frac{1}{x} - \frac{3}{3x-1} =\frac{-1}{3x^2-x}](https://tex.z-dn.net/?f=%5Cfrac%7B%283x-1%29%27%7D%7B3x-1%7D%20%3D%5Cfrac%7B3%7D%7B3x-1%7D%3C%2Fp%3E%3Cp%3Ef%27%28x%29%3Dg%27%28x%29%20-%20h%27%28x%29%20%3D%5Btex%5D%5Cfrac%7B1%7D%7Bx%7D%20-%20%5Cfrac%7B3%7D%7B3x-1%7D%20%3D%5Cfrac%7B-1%7D%7B3x%5E2-x%7D)
Answer:
D
Step-by-step explanation:
f(x) = -3x^3 + x^2 – 3 f(2) means that wherever you see a x, put in a 2.
f(2)= -3(2)^3 + (2)^2 - 3
f(2) = -3*8 + 4 - 3
f(2) = - 24 + 1
f(2) = - 23
(x + 3) (x + 2) = 0
To solve it, the most appropriate technique is:
1.) zero product property
The solutions are:
(x + 3) = 0
x = -3
(x + 2) = 0
x = -2
x² + 6 = 31
To solve it, the most appropriate technique is:
2.) square root property
x² = 31-6
x² = 25
x = +/- root (25)
x = +/- 5
The solutions are:
x = 5
x = -5
